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NISA [10]
3 years ago
13

Does 4 have an infinate number of significant digits?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
6 0
4 is Significant! It doesn’t have 0’s
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A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
3 years ago
Volume of the sample?
galina1969 [7]
Volume of water plus sample minus volume of water in graduated cylinder
3 0
3 years ago
For each of the following substituents, indicate whether it withdraws electrons inductively, donates electrons by hyperconjugati
AveGali [126]

Answer:

a. withdraws electrons inductively

b. donates electrons by hyperconjugation

c. donates electrons by resonance

d.  withdraws electrons inductively

Explanation:

a.  The bromide ion is a highly electronegative ion (in the halide series). Electronegative substituents on acids increase the acidity by inductive electron withdrawal method. The higher the electronegativity of a substance, the greater the acidity. The halogens have this order of electronegativity:

F > Cl > Br>I

b.  The carboxyl groups have a stabilization of the sigma and pi bonds. This is achieved through a special delocalization of electrons.  Because of the delocalization, hyperconjugation is the result effect.

c. The NHCH₃ group has a highly electonegative nitrogen atom that pulls the electron cloud towards itself. In this case, it withdraws electrons inductively. As a result, it donates electrons by resonance.

d. The OCH₃ group has a highly electonegative oxygen atom. This oxygen atom withdraws electron cloud towards itself. As a result, it withdraws electrons inductively.

3 0
3 years ago
H2(g) + I2(g) ↔2HI(g) + heat. If more I2 is added, in what direction will the equilibrium shift? Group of answer choices
uranmaximum [27]

Answer:

Towards the products, or to the right

Explanation:

There are no provided answer choices, but the answer should be <u>to the right.</u>

By Le Chatelier's principle, which basically can be summarized as "if you mess with chemistry, chemistry messes back", if more reactants are added, the equilibrium will shift to the right towards the products in order to make more products and counteract the increase in I₂.

7 0
3 years ago
Give the ratio that balances out the following equation: ___Cr + ___Pb(NO3)4 ---&gt; ___ Cr(NO3)3 + ____ Pb
gizmo_the_mogwai [7]

Answer:  Ratio : 4, 3, 4, 3 are the answers.

Explanation:

6 0
3 years ago
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