Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
(1.75 + 2 x 0.25 + 5 x 0.05) x 24= 17
Answer:
PQ = 3.2
Step-by-step explanation:
You must use the addition property of equality, and subtract 16 from the of the 5x, and add it to the other side.
After that, you have 5x = 16
You then divide both sides by 5.
5x/5 = 1x = x
16/5 = 3.2
x = 3.2
Therefore, the side 'PQ' is equal to 3.2
Brainliest appreciated!
Answer:
x = -2 and y = 1
Step-by-step explanation:
for details see image