Answer:
11.4 m/s
Explanation:
The expression for the Centripetal acceleration is :

Where, a is the accleration
v is the velocity around circumference of circle
R is radius of circle
In the given question,
a = g = Acceleration due to gravity as the car is at top = 
v = ?
R = 13.2 m
So,


<u>v = 11.4 m/s</u>
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consider the motion along the X-direction
X = horizontal displacement = 80 m
= initial velocity along the x-direction = v Cos60
t = time of travel
using the equation
X =
t
80 = (v Cos60) (t)
t = 160/v eq-1
consider the motion in vertical direction :
Y = vertical displacement = 20 m
= initial velocity in Y-direction = v Sin60
a = acceleration = - 9.8 m/s²
t = time of travel = 160/v
using the equation
Y =
t + (0.5) a t²
20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²
v = 32.5 m/s
Answer:
option B
−1.92 m/s2
Explanation:
Given in the question,
time took by truck to slow down = 3.56 sec
initial speed of truck = 112 km/h
final speed of truck = 87.4 km/h
1 km/h = 0.277778 m/s
112 = 31.1 m/s
87.4 = 24.28 m/s
Formula use to calculate the acceleration
v - u = at
where v is final speed
u is initial speed
a is acceleration
t is time
plug values in the equation
24.28 - 31.1 = a(3.56)
-6.8 = a(3.56)
a = -6.8 / 3.56
a = -1.9 m/s²
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