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melomori [17]
3 years ago
7

A force of 5.25 newtons acts on an object of unknown mass at a distance of 6.9 × 108 meters from the center of Earth. To increas

e the force to 2.5 times its original value, how far should the object be from the center of Earth?
Physics
2 answers:
alexira [117]3 years ago
7 0

Answer:

4.36 x 10^8 m

Explanation:

Let the mass of earth is M and unknown mass is m.

According to the Newton's law of gravitation, force between two objects is given by

F = G\frac{M m}{d^{2}}

Here, F = 5.25 N, d = 6.9 x 10^8 m

5.25 = G\frac{M m}{(6.9\times 10^{8})^{2}}       .... (1)

Now, F' = 2.5 F and d be the distance

2.5\times 5.25 = G\frac{M m}{(d)^{2}}            ..... (2)

Divide equation (1) by equation by (2)

\frac{1}{2.5} = \left ( \frac{d}{6.9\times 10^{8}} \right )^{2}

d = 4.36 x 10^8 m

NemiM [27]3 years ago
5 0
The force between two objects is calculated through the equation, 
                        F = Gm₁m₂/d²
where m₁ and m₂ are the masses of the objects. In this case, an unknown mass and Earth. d is the distance between them and G is universal gravitation constant. 

In the second case, if the force is to become 2.5 times the original and all the variables are constant except d then,
                       2.5F = Gm₁m₂ / (D²)
                                D = 0.623d

Subsituting the known value of d,
                                D = 0.623(6.9 x 10^8) = <em>4.298 x 10^8 m</em>
                           
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2.0 kg

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A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i
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Answer:

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3 years ago
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. Th
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Answer:

a) F_{fric} = 692 N

b) F_{applied} = 932 N

Explanation:

a)

According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object  in all directions.

F_{net}  ∝ a

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b)

According to newton's second law of motion,

F_{net}  ∝ a

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If we assume the same friction and acceleration between player's feet and ground as calculated in part a

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Mass = M = m₁ + m₂ = 110 kg + 90 kg

= 200 kg

F_{applied} = ?

F_{applied} - 692 N = (200)(1.2)

F_{applied} = 692 + 240

F_{applied} = 932 N

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