Answer:
Fe2+ (aq) + 2e -> Fe(s)
Explanation:
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reaction:
Mg(s) + Fe2+ (aq) —>Mg2+ (aq) + Fe(s)
Magnesium loses its two valance electrons and oxidized while iron accept two electrons get reduced.
Magnesium is reducing agent while iron is oxidizing agent.
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized.
When the acid is hydrolyzed, the reaction is
HA --> H⁺ + A⁻
So,
Ka = [H⁺][A⁻]/[HA]
Apply the ICE approach:
HA --> H⁺ + A⁻
I 0.3 0 0
C -X +X +X
E 0.3-X X X
Ka = [X][X]/[0.3-X]
X = H⁺ = A⁻
The formula for pH is:
pH = -log[X]
5.2 = -log[X]
Solving for X,
X = 6.31*10⁻⁶
Therefore,
Ka = [6.31*10⁻⁶][6.31*10⁻⁶]/[0.3-6.31*10⁻⁶]
<span>Ka = 1.33×10⁻¹⁰</span>
Answer:
Option C.
Because the cations give away an electron and the anions accept electrons
It was a mixture bc it settled, and compounds dont do that
Answer:
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