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Natalija [7]
4 years ago
6

Which electromagnetic radiation can be seen with human eye?

Physics
2 answers:
SVEN [57.7K]4 years ago
6 0

Answer:

visible light and ultraviolet light

Explanation:

think about it, can you see anything else?

diamong [38]4 years ago
4 0

The range of visible wavelengths is 400 to 700 nanometers. Ultraviolet light is the radiation from the sun that causes a sunburn when you have been outside too long on a sunny day. But, watch out! You can't see ultra-violet light, so you can still get sunburned on a cloudy day.

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Imagine that an uncharged pith ball is brought into the electrostatic field of a charged rod. The side of the pith ball closest
nataly862011 [7]

As per the question the uncharged pith ball is taken towards the electrostatic field of a charged rod.

It is told that the side of the pith ball is closest to the negatively charged end of the rod .

The pith ball was initially neutral.The electrons in the atom were oriented in their respective orbits.

Whenever it is taken towards the negative end of the rod,the electrons present in the ball will not stick to their orbit .Basically the closest electrons will suffer electrostatic repulsive force and will come out their orbits.They will move towards the other end of the pith ball.Hence the closest side of the pith ball will acquire  positive charges and other side will be negative.

The bound charges nearest to the charged rod is called induced positive charges and bound negative  charges present at the other end are called free bound charges.The induced charges and free charges are equal in amount.Hence the pith ball is neutral.

Hence from above we see that only option B  is right.

5 0
3 years ago
Read 2 more answers
An instructor’s laser pointer produces a beam of light with a circular cross section of diameter 0.900 mm and a total power outp
il63 [147K]

Answer:

E_0 = 2180.53N/C.

B_0 = 7.27*10^{-6}T.

U_{avg} = 4.2*10^{-5}J/m^3.

Explanation:

The Intensity I of the beam is

I = P /A

The diameter of the beam is 0.900mm; therefore, the area is

A = \pi( \dfrac{0.900*10^{-3}}{2} )^2

A = 6.36*10^{-7}m^2

and since P = 4.00*10^{-3}W, the intensity of the beam is

I = \dfrac{4.00*10^{-3}W}{6.36*10^{-7}m^2}

\boxed{I = 6289.3W/m^2.}

Now, the intensity I is related to E_0 by the relation

I = \dfrac{E_0^2}{2\mu_0 c}

solving for E_0 we get

E_0 = \sqrt{2\mu_0 c I}

putting in the numbers we get:

E_0 = \sqrt{2(1.26*10^{-6}) (3*10^8) (6289.3)}

\boxed{E_0 = 2180.53N/C.}

The amplitude of magnetic field B_0 is related to E_0 by

B_0 = \dfrac{E_0}{c}

putting in numerical values we get:

B_0 = \dfrac{2180.53}{3*10^8}

\boxed{B_0 = 7.27*10^{-6}T. }

The average energy density of the laser light is

U_{avg} = \epsilon_0 E_0^2

U_{avg} = (8.85*10^{-12}) (2180.53)^2

\boxed{U_{avg} = 4.2*10^{-5}J/m^3.}

8 0
4 years ago
11. Explain why in terms of gravity and air resistance and the 2nd law, objects in free fall regardless of mass hit at the same
Alchen [17]

Answer:

When an object is dropped, it accelerates toward the center of Earth. Newton's second law states that a net force on an object is responsible for its acceleration. If air resistance is negligible, the net force on a falling object is the gravitational force.

7 0
3 years ago
What causes competition among organisms?
dimaraw [331]
Both organisms attempt to use the same limited sources
5 0
3 years ago
How much of the Moon is always illuminated one time? Explain your answer.
Natalija [7]

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

6 0
3 years ago
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