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Sidana [21]
4 years ago
11

How does the path at which a ray of light strikes a prism compare to the path after emergence from the other side?

Physics
1 answer:
fgiga [73]4 years ago
5 0
This is the reason why the path at which a ray of light strikes a prism is different to the path after emergence from the other side. There is a refraction of light ray when the light passes from one medium to another at angle. Its speed changes. The bend is in one direction if the material it enters is denser, and other direction if less dense. The amount of bending is different because of different wavelengths.
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A car is traveling at a constant speed of 12 m/s when the driver accelerates the car reaches a speed of 26 m/s in 6 s what is th
alexandr1967 [171]
26-12= 14

14/6=2 1/3 m/s
5 0
3 years ago
Light shines through a single slit whose width is 5.6 × 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
Mrac [35]

Answer:

462 nm

Explanation:

Given: width of the slit, d = 5.6 × 10⁻⁴ m

Distance of the screen, D = 4.0 m

Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m

First dark fringe means n =1

Wavelength of the light, λ = ?

\beta = \frac{\lambda D}{d}\\ \Rightarrow \lambda = \frac{d \beta}{D} =\frac{5.6\times 10^{-4} \times 3.3 \times 10^{-3}}{4.0} = 4.62 \times 10^{-7}m = 462 nm

5 0
3 years ago
The graph shows how the vertical velocity of a parachutist changes from the moment the parachutist jumps from the aircraft until
soldi70 [24.7K]

Answer:

BUT WHY

Explanation:

4 0
4 years ago
17,874,000 what is the value of 1
kotegsom [21]
Salutations!

17,874,000 what is the value of 1?

The value of 1 is 10 million. The place value would be 10,000,000.

Hope I helped.
3 0
3 years ago
Read 2 more answers
How much work is done by a student carrying a 12 kg backpack while accelerating at a rate of 0.51 m/s2 over a distance of 5.0 m?
Klio2033 [76]

The amount of work done by the student in carrying the backpack is 30.6 J

<h3>Definition of workdone </h3>

Workdone is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = Force (F) × distance (d)

Wd = Fd

Also,

Force (F) = mass (m) × acceleration (a)

F = ma

Therefore,

Wd = (ma) × d

With the above formula, we can obtain the work done by the student.

<h3>How to determine the Workdone </h3>

From the question given above, the following data were obtained:

  • Mass (m) = 12 Kg
  • Acceleration (a) = 0.51 m/s²
  • Distance (d) = 5 m
  • Workdone (Wd) =?

Wd = (ma) × d

Wd = 12 × 0.51 × 5

Wd = 30.6 J

Learn more about workdone:

brainly.com/question/14667371

8 0
3 years ago
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