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max2010maxim [7]
4 years ago
8

What is the process of change in a crust due to the motion of hot material underneath?(answer)?

Physics
1 answer:
frutty [35]4 years ago
5 0
Im not exactly sure but I think the answer is techtonic plates collide
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Sunlight strikes a solar panel.which is then used to power the lights in the house. What are the energy transformation taking pl
AVprozaik [17]

Answer:Thermal energy to electric energy to light energy

6 0
4 years ago
Which is not a unit of heat? joule British Thermal Unit calorie kelvin
insens350 [35]
The Joule, the BTU, and the calorie are units of energy,
in the form of heat or in any other form.

The Kelvin is a unit of temperature.
8 0
3 years ago
Read 2 more answers
Suppose that the speed of an electron traveling 2.0 km/s is known to an accuracy of 1 part in 105 (i.e., within 0.0010%). What i
OverLord2011 [107]

Answer: 2.89(10)^{-3} m

Explanation:

The <u>Heisenberg uncertainty principle</u> postulates that the fact each particle has a wave associated with it, imposes restrictions on the ability to determine its position and speed at the same time.  

In other words:  

It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle. Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.

Mathematically this principle is written as:

\Delta x \geq \frac{h}{4 \pi m \Delta V} (1)

Where:

\Delta x is the uncertainty in the position of the electron

h=6.626(10)^{-34}J.s is the Planck constant

m=9.11(10)^{-31}kg is the mass of the electron

\Delta V is the uncertainty in the velocity of the electron.

If we know the accuracy of the velocity is 0.001\% of the velocity of the electron V=2 km/s=2000 m/s, then \Delta V is:

\Delta V=2000 m/s(0.001\%)

\Delta V=2000 m/s(\frac{0.001}{100})

\Delta V=2(10)^{-2} m/s (2)

Now, the least possible uncertainty in position \Delta x_{min} is:

\Delta x_{min}=\frac{h}{4 \pi m \Delta V} (3)

\Delta x_{min}=\frac{6.626(10)^{-34}J.s}{4 \pi (9.11(10)^{-31}kg) (2(10)^{-2} m/s)} (4)

Finally:

\Delta x_{min}=2.89(10)^{-3} m

5 0
3 years ago
In the simple circuit shown, what is the resistance, R? (Remember that V = I*R)
Nookie1986 [14]
B
Bensbsbng f fudge dndjdjd d djdjdbd
5 0
3 years ago
An arrow is shot at an angle 38 ◦ with the horizontal. It has a velocity of 46 m/s. How high will the arrow go?
Klio2033 [76]

Answer:

40·919 m

Explanation:

Initial velocity of the arrow = 46 m/s

Angle at which it is thrown from horizontal = 38°

<h3>At the maximum height, the vertical component of velocity will be 0</h3>

Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s

From the formula

<h3>v² - u² = 2 × a × s</h3>

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Considering the formula in vertical direction and taking upward direction as positive

v = 0

u = 28·32 m/s

a = - g = - 9·8 m/s²

Let s be the maximum height

- 28·32² = - 2 × 9.8 × s

⇒ s = 40·919 m

∴ The arrow will go 40·919 m high

8 0
3 years ago
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