Answer:
I = 
(K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr
Now integrating we get
I = 
I = (K+5) 2π
I = (K+5) 2π 
I = (K+5)
Answer:
I only really know the "How do we use these EM waves in our lives?" part srry
Explanation:
EM waves are used to make sure you cellphone, radio, TV, and etc. have service/ connection.
Answer:
There are 6 electrons in the outermost shell.
Explanation:
Sulphur is a non-mettalic element which is in the period 3 and group .6on the periodic table. It has an atomic number of 16 and a Mass number of 32. Atomic number tells you the number of electrons in an electrically neutral atom. It has the electronic configuration of 1s2 2s2 2p6 3s2 3p4.
The orbitals have a formula 2n^2 where n = 0, 1, 2, 3 etc.
In the shells, n = 1 so there are 2 electrons. For n = 2, 2*(2)^2 = 8 electrons. So, 16 - (8 + 2) = 6 electrons in the 3 shell (outermost shell)
Therefore from the electronic confriguration above, there are 6 electrons in the outermost shell.
Number two because the sun emits heat in the form of light to earth
