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alexira [117]
4 years ago
7

How much force is required to accelerate a 5kg mass pushed by a 10n force

Physics
1 answer:
Rama09 [41]4 years ago
4 0
2 m/s^2


^2 means squared
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Answer:

and unbalanced force

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if balanced then the object will exert as much force as you are. its like pushing against a wall. and unblanced force is like pushing against a chair

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3 years ago
What is a common noun?
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I HOPE IT WILL HELP YOU.

Thank you.

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2 years ago
A series RCL circuit consists of a 50 Ω resistor, 500 Ω capacitor, and a 500 Ω inductor. What is the angle of impedance?
lbvjy [14]

Answer:

Zero

Explanation:

here, the inductive reactance and the capacitive reactance is same, so this is the condition for resonance.

In the condition for resonance,

the circuit and the voltage in the circuit is in the same phase and the impedance of the circuit is minimum which is equal to the resistance of the circuit.

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3 years ago
Lenz’s law states that an induced magnetic field in a conductor true or false
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Let's say there's a magnetic field B passing through a conductor loop with an area A. The magnetic flux through the loop, if B is constant and perpendicular to the loop, is B multiplied by A. Now let's say the magnetic flux is changing. This can be caused by a combination of the strength of B changing, A changing, or the orientation of B or the loop changing.

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5 0
4 years ago
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distanc
dem82 [27]

Explanation:

It is known that the relation between speed and distance is as follows.

               velocity = \frac{distance}{time}

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

         t_{bear} = \frac{(d + 29)}{6 m/s} ............. (1)

As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.

              t_{tourist} = \frac{d}{4.2} ............. (2)

Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

              t_{bear} = t_{tourist}

       \frac{(d + 29)}{6 m/s} = \frac{d}{4.2}

                   4.2d + 121.8 = 6d

                         d = \frac{121.8}{1.8}

                            = 67.66

Thus, we can conclude that the maximum possible value for d is 67.66.

5 0
3 years ago
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