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Nataliya [291]
3 years ago
10

reaction 1:CCl4⟶CH4 reaction 2:N2+3H2⟶2H3N reaction 3:2H2+2O2⟶2H2O+Au Which of the chemical reactions are NOT possible according

to Dalton's atomic theory?
Chemistry
1 answer:
olga nikolaevna [1]3 years ago
3 0

Clutch Prep

Ch.2 - Atoms & ElementsSee all chapters

Atomic Theory

See all sections

LearnAdditional Practice

Solution: Which of the following chemical reactions is/are NOT possible according to Dalton's atomic theory?a. reaction 1: CCl4 → CH4b. reaction 2: N2 + 3H2 → 2NH3c. reaction 3: 2H2 + O2 → 2H2O + Au

Problem

Which of the following chemical reactions is/are NOT possible according to Dalton's atomic theory?

a. reaction 1: CCl4 → CH4

b. reaction 2: N2 + 3H2 → 2NH3

c. reaction 3: 2H2 + O2 → 2H2O + Au

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Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer
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d_{1}=\frac{m}{V_{1}}\\\\&#10;V_{1}=395cm^{3}\\&#10;d_{1}=0,38\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ m=395cm^{3}*0,38\frac{g}{cm^{3}}=150,1g\\\\\\&#10;d_{2}=\frac{m}{V_{2}}\\\\&#10;m=150,1g\\&#10;d_{2}=11,3\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ V_{2}=\frac{150,1g}{11,3\frac{g}{cm^{3}}}\approx13,28cm^{3}
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Circle which of the following depend on the amount of matter present:
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Balance this equation. Pb(NO3)2(aq)+NaCl(aq) -&gt; NaNO3(aq)+PbCl2(s)
const2013 [10]

Answer:

Pb(NO3)2(aq) + 2NaCl(aq) -> 2NaNO3(aq)+PbCl2(s)

Explanation:

Pb(NO3)2(aq)+NaCl(aq) -> NaNO3(aq)+PbCl2(s)

This is how it starts out.

Left:

  • 2 NO3s
  • 1 Pb
  • 1 Na
  • 1 Cl

Right

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So the place to start with this equation is to bring the Cls up to 2

Pb(NO3)2(aq)+2NaCl(aq) -> NaNO3(aq)+PbCl2(s)

But the Nas are now out of kilter.

Pb(NO3)2(aq)+ 2NaCl(aq) -> NaNO3(aq)+PbCl2(s)

Now the right has a problem. There's only 1 Na

Pb(NO3)2(aq) + 2 NaCl(aq) -> 2NaNO3(aq)+PbCl2(s)

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5 0
2 years ago
A chemist is given a 3.00M solution of KBr and needs to measure out 0.733 moles of this solution. How many mL of the 3.00M KBr s
Charra [1.4K]

In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.

<h3>What is molarity?</h3>

Molarity (M) is a unit of concentration of solutions, and it is defined as the moles of a solute per liters of a solution.

  • Step 1: Calculate the liters of solution required.

A chemist has a 3.00 M KBr solution and wants to measure 0.733 moles of KBr. The required volume is:

0.733 mol × (1 L/3.00 mol) = 0.244 L

  • Step 2: Convert 0.244 L to mL.

We will use the conversion factor 1 L = 1000 mL.

0.244 L × (1000 mL/1 L) = 244 mL

In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.

Learn more about molarity here: brainly.com/question/9118107

7 0
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