Answer:
1255.4L
Explanation:
Given parameters:
P₁ = 928kpa
T₁ = 129°C
V₁ = 569L
P₂ = 319kpa
T₂ = 32°C
Unknown:
V₂ = ?
Solution:
The combined gas law application to this problem can help us solve it. It is mathematically expressed as;
P, V and T are pressure, volume and temperature
where 1 and 2 are initial and final states.
Now,
take the units to the appropriate ones;
kpa to atm, °C to K
P₂ = 319kpa in atm gives 3.15atm
P₁ = 928kpa gives 9.16atm
T₂ = 32°C gives 273 + 32 = 305K
T₁ = 129°C gives 129 + 273 = 402K
Input the values in the equation and solve for V₂;
V₂ = 1255.4L
Answer: 40cm^3
Explanation:
Since the The air today is approximately one-fifth oxygen, the approximate volume of oxygen in 200cm3 of air would be:
= 1/5 × 200
= 40cm
The answer is 40cm^3
1: their dna is found in the nucleiod
2: their cell wall acts as an area of protection, helps to maintain shape and prevent dehydration.
Answer:concentration
Explanation:
In the first, the particles are much more concentrated, or close together, than in the second, where the particles are much more sparse.