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Zigmanuir [339]
3 years ago
11

During heavy rain, a section of a mountainside measuring 2.5 km horizontally, 0.80 km up along the slope, and 2.0 m deep slips i

nto a valley in a mud slide.Assume that the mud ends up uniformly distributed over a surface area of the valley measuring 0.40 km 0.40 km and that mud has a density of 1900 kg/m3.What is the mass of the mud sitting above a 4.0 m2 area of the valley floor?
Physics
1 answer:
Crank3 years ago
4 0

Answer:

The mass of the mud is 3040000 kg.

Explanation:

Given that,

length = 2.5 km

Width = 0.80 km

Height = 2.0 m

Length of valley = 0.40 km

Width of valley = 0.40 km

Density = 1900 Kg/m³

Area = 4.0 m²

We need to calculate the mass of the mud

Using formula of density

\rho=\dfrac{m}{V}

m=\rho\times V

Where, V = volume of mud

\rho = density of mud

Put the value into the formula

m=1900\times4.0\times0.40\times10^{3}

m =3040000\ kg

Hence, The mass of the mud is 3040000 kg.

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Answer:

0.661 s, 5.29 m

Explanation:

In the y direction:

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t = 0.661 s

In the x direction:

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Find: Δx

Δx = v₀ t + ½ at²

Δx = (8 m/s) (0.661 s) + ½ (0 m/s²) (0.661 s)²

Δx = 5.29 m

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Murrr4er [49]

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c

Explanation:

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