The answer is 0.0430 following the rules of dividing and multiplying significant figures.
To determine the mass of elemental iron in the elixir, we need to understand the given values given above. We are given the following:
Mass of ferrous sulfate = 220 mg
Volume of the elixir = 5 mL
Mass of elemental iron / mass of ferrous sulfate = 0.2 mg Fe / mg ferrous sulfate
Therefore, from the given values, we simply multiply the mass of the ferrous sulfate in the elixir and the equivalent mass of elemental iron per mass of ferrous sulfate. We do as follows:
Mass of Fe = 220 mg ferrous sulfate ( 0.2 mg Fe / mg ferrous sulfate )
Mass of Fe = 44 mg
Lol what images you have to put images
