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Inga [223]
4 years ago
9

A ballistic pendulum is used to measure the speed of high-speed projectiles. A bullet A weighing 22 g is fired into a 2.6-kg woo

d block B suspended by a cord of length l = 2.2 m. The block then swings through a maximum angle of θ = 60°. Determine the initial speed of the bullet v0.

Physics
2 answers:
shepuryov [24]4 years ago
6 0

Answer:

v_{0}=554.19 m/s

Explanation:

We can use the conservation of momentum and energy.

Conservation of momentum

m_{1}v_{0}=(m_{1}+m_{2})V (1)

Where:

  • m(1) is the mass of the bullet
  • m(2) is the mass of the block
  • v(0) is the initial speed of the bullet
  • V(f) is the final speed of the system

Conservation of energy

We have kinetic energy at the beginning and we just have potential energy at the end because the block plus the bullet swing trough a maximum angle, it means they are at rest at that point.

\frac{1}{2}(m_{1}+m_{2})V^{2}=(m_{1}+m_{2})gh (2)

The height h will be:

h=L-Lcos(60)=L(1-cos(60))

h is the difference height between the initial and final positions.

So, using the equation (2) we can find V.

V^{2}=2gh

V=\sqrt{2gL(1-cos(60))}

V=\sqrt{2*9.81*2.2*(1-cos(60))}

V=4.65 m/s

Finally, putting this value in the equation (1), the v(1i) will be:

v_{0}=V\frac{(m_{1}+m_{2})}{m_{1}}

v_{0}=4.65\frac{(0.022+2.6)}{0.022}

v_{0}=554.19 m/s

I hope it helps you!

GrogVix [38]4 years ago
5 0

Answer: initial velocity of bullet = 50.72m/s

Explanation:

Detailed explanation and calculation is shown in the image below.

NB: the wooden block has an initial velocity u = 0 since it was at rest.

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a ultrasonic wave at 8x10^4 Hz is emitted into a vien where the speed of sound in blood is 1570 m/s. the wave reflects off the r
Aneli [31]

Answer: 0.392 m/s

Explanation:

The Doppler shift equation is:

f'=\frac{V+V_{o}}{V-V_{s}} f

Where:

f=8(10)^{4} Hz is the actual frequency of the sound wave

f'=8.002(10)^{4} Hz is the "observed" frequency

V=1570 m/s is the speed of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which are the red blood cells

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}

V_{s}=\frac{1570 m/s(8.002(10)^{4} Hz-8(10)^{4} Hz)}{8.002(10)^{4} Hz}

Finally:

V_{s}=0.392 m/s

3 0
3 years ago
Help needed,
Elena L [17]

Answer:

224 J

Explanation:

Step one:

given data

Force applied = 22.4 N

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<u>Required:</u>

the work done

Step two:

The expression for the work done is

WD= force*distance

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WD= 22.4*10

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3 0
3 years ago
A kicked soccer ball has an initial velocity of 25 meters per second at an angle of 40 degrees, above the horizontal.
Zinaida [17]

(1) The vertical magnitude of the ball's initial velocity is 16.075 m/s,

(2) The maximum height of the ball is 13.18 m

(1) To Calculate the vertical component of the ball's initial velocity, we use the formula below.

Formula:

  • Vy = Vsin∅........................ Equation 1

Where:

  • Vy = vertical component of the ball's initial velocity
  • V = Initial velocity of the ball
  • ∅  = angle to the horizontal.

From the question,

Given:

  • V = 25 m/s
  • ∅ = 40°

Substitute these values into equation 1

  • Vy = 25(sin40°)
  • Vy = 25×0.643
  • Vy = 16.075 m/s.

(2) To calculate the maximum height reached by the ball, we use the formula below.

Formula:

  • H = (Vy)²/2g............... Equation 2

Where:

  • g = Acceleration due to gravity = 9.8 m/s²

Substitute the value above into equation 2

  • H = (16.075)²/(2×9.8)
  • H = 13.18 m

Hence, (1) The vertical magnitude of the ball's initial velocity is 16.075 m/s, (b) The maximum height of the ball is 13.18 m.

Learn more about maximum height here: brainly.com/question/13665920

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