Question:
A high ____will have a short wavelength
Answer:
That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths
Explanation:
Hope it help
An average facility manager can build one new facility
during his or her career.
<span>A </span>facilities manager<span> is the ultimate organiser, making sure that a
workplace meets the needs of employees by managing all of the required
services. In this job, you will be responsible for the </span>management<span> of services and processes that support the core
business of an organisation.</span>
To solve this problem we will derive the expression of the precession period from the moment of inertia of the given object. We will convert the units that are not in SI, and finally we will find the precession period with the variables found. Let's start defining the moment of inertia.

Here,
M = Mass
R = Radius of the hoop
The precession frequency is given as

Here,
M = Mass
g= Acceleration due to gravity
d = Distance of center of mass from pivot
I = Moment of inertia
= Angular velocity
Replacing the value for moment of inertia


The value for our angular velocity is not in SI, then


Replacing our values we have that


The precession frequency is




Therefore the precession period is 5.4s
Answer:
The energy of photon, 
Explanation:
It is given that,
Voltage of anode, 
We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.

e is charge of electron


So, the maximum energy of the x- ray radiation is
. Hence, this is the required solution.
Answer:
its a solid but can flow
Explanation:
those answers to choose from are wrong