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4 years ago

3. When 10^14 electrons are removed from a neutral metal sphere, the charge on the sphere

Physics

1 answer:

Umnica [9.8K]4 years ago

4 0

Answer:

Β. 16 με

Explanation:

Data provided in the question

Number of electrons removed = 10^14

And, the charge on one electron = $1.6\times 10^ {-19C}$

Based on the above information, the charged on the sphere is

Therefore when we remove the electrons

So, the equation would be

$10^{14} \times 1.6 \times 10^{-19 C}$

= $1.6 \times 10$

Therefore the same amount of the positive charged would be developed

Hence, the correct option is B.

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When light travels from one medium to another with a different index of refraction, how is the light's frequency and wavelength

lbvjy [14]

Answer:

The frequency does not change, but the wavelength does

Explanation:

Here are the options

A. When a light wave travels from a medium with a lower index of refraction to a medium with a higher index of refraction, the frequency changes and the wavelength does not.

B. The frequency does change, but the wavelength remains unchanged.

C. Both the frequency and wavelength change.

D. When a light wave travels from a medium with a lower index of refraction to a medium with a higher index of refraction, neither the wavelength nor the frequency changes.

E. The frequency does not change, but its wavelength does.

When light goes through one medium to the next, the frequency doesn't really change seeing as frequency is dependent on wavelength and light wave velocity. And when the wavelength shifts from one medium to the next.

$n= \frac{C}{V} \ and\ \frac{\lambda_o}{\lambda_m}$

where $\lambda_o$ indicates wavelength in vacuum

$\lambda_m$ indicates wavelength in medium

n indicates refractive index

v indicates velocity of light wave

c indicates velocity of light

And wavelength is medium-dependent. Frequency Here = v $\lambda$ and shift in wavelength and velocity, not shifts in overall frequency.

Therefore the correct option is E

6 0

3 years ago

An Olympic runner complete the 200 m sprint and 23 seconds. What is the runners average speed (round your answer to the nearest

kipiarov [429]

Should be 8.7 m/s. Just divide 200 by 23 and round from there.

3 0

3 years ago

Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example

nlexa [21]

Answer:

The maximum emf that can be generated around the perimeter of a cell in this field is $1.5732*10^{-11}V$

Explanation:

To solve this problem it is necessary to apply the concepts on maximum electromotive force.

For definition we know that

$\epsilon_{max} = NBA\omega$

Where,

N= Number of turns of the coil

B = Magnetic field

$\omega =$ Angular velocity

A = Cross-sectional Area

Angular velocity according kinematics equations is:

$\omega = 2\pi f$

$\omega = 2\pi*61.5$

$\omega =123\pi rad/s$

Replacing at the equation our values given we have that

$\epsilon_{max} = NBA\omega$

$\epsilon_{max} = NB(\pi (\frac{d}{2})^2)\omega$

$\epsilon_{max} = (1)(1*10^{-3})(\pi (\frac{7.2*10^{-6}}{2})^2)(123\pi)$

$\epsilon_{max} = 1.5732*10^{-11}V$

Therefore the maximum emf that can be generated around the perimeter of a cell in this field is $1.5732*10^{-11}V$

6 0

4 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change

olga55 [171]

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

7 0

3 years ago

What causes air to move or circulate from one place to another?

MAXImum [283]

Answer:

Explanation:

simple

3 0

3 years ago

Read 2 more answers