Answer:
non linear square relationship
Explanation:
formula for centripetal force is given as
a = mv^2/r
here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have
a = constant × v^2
a α v^2
hence non linear square relationship
Explanation:
The momentum of the three objects are as follow :
11 kg-m/s, -65 kg-m/s and -100 kg-m/s
Before collision, the momentum of the system is :
![P_i=11+(-65)+(-100)\\\\P_i=-154\ kg-m/s](https://tex.z-dn.net/?f=P_i%3D11%2B%28-65%29%2B%28-100%29%5C%5C%5C%5CP_i%3D-154%5C%20kg-m%2Fs)
After collison, they move together. It means it is a case of inelastic collision. In this type of collision, the momentum of the system remains conserved.
It would mean that, after collision, momentum of the system is equal to the initial momentum.
Hence, final momentum = -154 kg-m/s.
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Hope this helps!
Answer:
A ball being dropped to the ground