Answer:
How to find the maximum height of a projectile?
if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...
if α = 45°, then the equation may be written as: ...
if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.
Explanation:
The relationship between work and energy is that work can transfer energy between objects and cause a change in the form of energy.
<h3>What is energy?</h3>
Energy is simply defined as the ability to do work.
Energy possessed by any object or matter enables it to do work of various forms.
Energy can be transferred from one object to another. Also, energy can be transformed into various forms.
Therefore, the relationship between work and energy is that work can transfer energy between objects and cause a change in the form of energy.
Learn more about energy and work at: brainly.com/question/13881533
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You could be counting while running
Answer:
C. perpendicular to one another and perpendicular to the direction of wave propagation.
Explanation:
An Electromagnetic wave (EM wave) is a wave having both electric and magnetic components in it. These wave radiates electromagnetic energy while propagating through the space. The electric and magnetic field component of the wave have an angle of 90° to each other aming them perpendicular while they both are perpendicular to the direction of wave propagation as well.
Some examples of EM waves are: UV rays, IR radiation, Radio waves etc. These waves propagate at the speed of light in vacuum.
The crate is in equilibrium. Newton's second law gives
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0
where
• <em>n</em> = magnitude of the normal force
• <em>mg</em> = weight of the crate
• <em>p</em> = mag. of push exerted by movers
• <em>f</em> = mag. of kinetic friciton, with <em>f</em> = 0.60<em>n</em>
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It follows that
<em>p</em> = <em>f</em> = 0.60<em>mg</em> = 0.60 (43.0 kg) <em>g</em> = 252.84 N
so that the movers perform
<em>W</em> = <em>p</em> (10.4 m) ≈ 2600 J
of work on the crate. (The <em>total</em> work done on the crate, on the other hand, is zero because the net force on the crate is zero.)
