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4 years ago

I need help cause my science teacher won’t help me can some one please help me

Physics

1 answer:

Jet001 [13]4 years ago

3 0

All you do is 0.5 times the mass times the kenetic energy hope this helps

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An object exhibits SHM with an angular frequency w = 4.0 s-1 and is released from its maximum displacement of A = 0.50 m at t =

vivado [14]

Explanation:

It is given that,

Angular frequency, $\omega=4\ s^{-1}$

Maximum displacement, A = 0.5 m at t = 0 s

We need to find the time at which it reaches its maximum speed. Firstly, we will find the maximum velocity of the object that is exhibiting SHM.

$v_{max}=A\times \omega$

$v_{max}=0.5\times 4$

$v_{max}=2\ m/s$ ............(1)

Acceleration of the object, $a=\omega^2A$

$a=4^2\times 0.5$

$a=8\ m/s^2$ ...............(2)

Using first equation of motion we can calculate the time taken to reach maximum speed.

$v=u+at$

$t=\dfrac{v-u}{a}$

$t=\dfrac{2-0}{8}$

t = 0.25 s

So, the object will take 0.25 seconds to reach its maximum speed. Hence, this is the required solution.

4 0

3 years ago

A solid sphere of radius R carries a fixed, uniformly distributed charge q. Obtain an expression for the magnitude of the electr

NISA [10]

Answer:

The electric field outside the sphere will be $\dfrac{qr}{4\pi\epsilon_{0}R^3}$ .

Explanation:

Given that,

Radius of solid sphere = R

Charge = q

According to figure,

Suppose r is the distance between the point P and center of sphere.

If $\rho$ be the volume charge density,

Then, the charge will be,

$q=\rho\times\dfrac{4}{3}\pi R^3$ .....(I)

Consider a Gaussian surface of radius r.

We need to calculate the electric field outside the sphere

Using formula of electric field

$\oint{\vec{E}\cdot \vec{dA}}=\dfrac{Q}{\epsilon_{0}}$

$E\times4\pi r^2=\dfrac{\rho\dotc \dfrac{4}{3}\pi r^3}{\epsilon_{0}}$

Put the value from equation (I)

$E\times4\pi r^2=\dfrac{qr^3}{\epsilon_{0}R^3}$

$E=\dfrac{qr}{4\pi\epsilon_{0}R^3}$

Hence, The electric field outside the sphere will be $\dfrac{qr}{4\pi\epsilon_{0}R^3}$ .

4 0

3 years ago

Please help 9.2.1 project in science just ned an example

olga55 [171]

Answer:

Give me what kind of example you need please so I can help you. Put it in the comments.

Explanation:

3 0

3 years ago

To find some of the parameters characterizing an object moving in a circular orbit.The motivation for Isaac Newton to discover h

tamaranim1 [39]

Answer:

$K = \frac{GMm}{2r}$

$T^2 = 4\pi^2(\frac{r^3}{GM})$

Explanation:

As we know that for a satellite the force of gravitation is equal to the centripetal force

so we will have

$F = \frac{GMm}{r^2}$

$\frac{mv^2}{r} = \frac{GMm}{r^2}$

so we know that kinetic energy is given as

$K = \frac{1}{2}mv^2$

so we have

$K = \frac{GMm}{2r}$

now for time period we know

$T = \frac{2\pi r}{v}$

from above expression of kinetic energy we have

$v = \sqrt{\frac{GM}{r}}$

so we have

$T = \frac{2\pi r}{\sqrt{\frac{GM}{r}}}$

so square of time period is given as

$T^2 = 4\pi^2(\frac{r^3}{GM})$

3 0

4 years ago

An electron moves on a circular orbit in a uniform magnetic field of 7.83×10-4 T. The kinetic energy of the electron is 55.3 eV.

yuradex [85]

Answer:

3.9E-8

Explanation:

We know that

Mv²/r = Bqv

r= mv/Bq

But E is 1/2mv² which is 5.53eV

m²v² =2m x 5.53eV

mv = √( 2 x 9.1E-31)

r= √( 2 x9.1E-31 x 5.53)/ 7.83x10^-4 x1.6E-19

= 3.9x10-8cm

Explanation:

7 0

3 years ago