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Zina [86]
4 years ago
6

Gazala makes a graphic organizer to compare nuclear fission and nuclear fusion. Which labels belong in the regions marked X and

Y? X: Provides household electricity Y: Has rods containing uranium X: Provides household electricity Y: Requires high temperature and pressure X: Converts mass into energy Y: Does not produce usable amounts of energy X: Converts mass into energy Y: Is controlled by neutron absorption
Chemistry
2 answers:
alex41 [277]4 years ago
9 0

Answer:

X: Converts mass into energy

Y: Is controlled by neutron absorption

Explanation:

Sedaia [141]4 years ago
5 0
<span>Some important concepts and facts that will let you to label each statement:

1) Both fusion and fission are nuclear reactions by which atoms change and create energy.

2) Fusion is the kind reaction that occurs in the sun, at extreme high temperatures and pressures.

3) Fusion is the union of two lighter atoms into a larger one.

4) Fission is the division of one atom into two lighter atoms.

5) Fussion creates much more energy than fission and create less radioactive material than fission, but scientist have not found how to control it.

6) Fission is used in nuclear plants to generate power because it can be controlled.

7) Fusion is not used to generate power because the extreme conditions needed and lack of control.

8) Fission reactors use uranium rods to control the chain reactions by absorbing neutrons.


X: Provides household electricity ---> FISSION     


Y: Has rods containing uranium ----> FISSION


Y: Requires high temperature and pressure -----> FUSION


X: Converts mass into energy ----> FISSION           

Y: Does not produce usable amounts of energy ----> FUSION

Y: Is controlled by neutron absorption  ----> FISSION</span>
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What is the limiting reactant when 4 mol P4 and 4 mol S8 react.
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Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

8 P₄ + 3 S₈ → 8 P₄S₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • P₄: 8 moles
  • S₈: 3 moles
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<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?

moles of P_{4} =\frac{4 moles of S_{8} x8 moles of P_{4} }{3 moles of S_{8}}

<u><em>moles of P₄= 10.667 moles</em></u>

But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.

Learn more about the reaction stoichiometry:

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How many grams of zinc would be required to produce 9.65g of zinc hydroxide
Effectus [21]

The question is incomplete, here is the complete question:

How many grams of zinc would be required to produce 9.65g of zinc hydroxide

Zn+2MnO₂+H₂O→Zn(OH)₂+Mn₂O₃

<u>Answer:</u> The mass of zinc required is 6.35 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of zinc hydroxide = 9.65 g

Molar mass of zinc hydroxide = 99.4 g/mol

Putting values in equation 1, we get:

\text{Moles of zinc hydroxide}=\frac{9.65g}{99.4g/mol}=0.0971mol

The given chemical equation follows:

Zn+2MnO_2+H_2O\rightarrow Zn(OH)_2+Mn_2O_3

By Stoichiometry of the reaction:

1 mole of zinc hydroxide is produced from 1 mole of zinc

So, 0.0971 moles of zinc hydroxide will be produced from = \frac{1}{1}\times 0.0971=0.0971mol of zinc

Now, calculating the mass of zinc from equation 1, we get:

Molar mass of zinc = 65.4 g/mol

Moles of zinc = 0.0971 moles

Putting values in equation 1, we get:

0.0971mol=\frac{\text{Mass of zinc}}{65.4g/mol}\\\\\text{Mass of zinc}=(0.0971mol\times 65.4g/mol)=6.35g

Hence, the mass of zinc required is 6.35 grams

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3 years ago
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