According to the equation you have 1 mole of C2H4 and 3 moles of O2.
1 • (22.4L / 270L) = 3 • (22.4L / x)
1/270L = 3/x
x = 3(270) / 1
x = 810 L
810 Liters of oxygen will react with 270 liters of ethene (C2H4) at STP
I believe the answer is Caloric Theory
Answer: put 2 in front of NaOH and 2 also in front of H2O
Explanation: 2NaOH + H2CO3 —> Na2CO3 + 2H2O
A covalent bond is formed between two non-metals that have similar electronegativities.
An <em>i</em><em>o</em><em>n</em><em>i</em><em>c</em><em> </em><em>b</em><em>o</em><em>n</em><em>d</em> is formed between a metal and a non-metal. Non-metals(-ve ion) are "stronger" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond.