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Alchen [17]
4 years ago
12

The total volume in milliliters of a glucose-water solution is given by the equation below: V = 1001.93 + 111.5282m + 0.64698m2

where m is the molality of the solution. The partial molar volume of glucose ?glucose, is the slope of a V versus m curve, (?V/?m). Find the partial molar volume of glucose in a 0.100m solution of glucose in water
Physics
1 answer:
Ostrovityanka [42]4 years ago
5 0

Answer:

111.657596

Explanation:

The expression of volume is given by

V=1001.93+111.5282+0.64698m^2

Partially differentiating the term we get

\dfrac{\partial V}{\partial x}=\dfrac{\partial (1001.93+111.5282+0.64698m^2)}{\partial x}\\\Rightarrow \dfrac{\partial V}{\partial x}=111.5282+2\times 0.64698m\\\Rightarrow \dfrac{\partial V}{\partial x}=111.5282+1.29396m

m = 0.100

\dfrac{\partial V}{\partial x}=111.5282+1.29396\times 0.100\\\Rightarrow \dfrac{\partial V}{\partial x}=111.657596

The partial molar volume of glucose is 111.657596

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A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr
Ksivusya [100]

a) The initial speed of the bullet is 330.5 m/s

b) The collision is inelastic

c) The impulse is -2.97 kg m/s

Explanation:

a)

The energy lost by the block while sliding (which is equal to the work done by friction) is equal to the kinetic energy of the block after the bullet has been embedded into it, therefore we can write

KE=W

\frac{1}{2}(M+m)v^2=(\mu (M+m)g) d

where

M = 1.20 kg is the mass of the block

m = 9.00 g = 0.009 kg is the mass of the bullet

v is the combined speed of bullet+block after the collision

\mu = 0.20 is the coefficient of friction

g=9.8 m/s^2 is the acceleration of gravity

d = 0.310 m is the distance through which the block slides

Solving for v,

v=\sqrt{2gd}=\sqrt{2(9.8)(0.310)}=2.46 m/s

This is the final velocity of the block+bullet after the collision.

Now we can apply the law of conservation of momentum: in fact, the total momentum of the system before the collision must be equal to the total momentum after the collision, so we get

mu+MU = (m+M)v

where

u is the initial velocity of the bullet

U = 0 is the initial velocity of the block (initially at rest)

v = 2.46 m/s

Solving for u,

u=\frac{(m+M)v}{m}=\frac{(0.009+1.20)(2.46)}{0.009}=330.5 m/s

b)

To check whether the collision is elastic or inelastic, we just need to compare the total kinetic energy before and after the collision.

Before the collision, we have:

K_i = \frac{1}{2}mu^2 = \frac{1}{2}(0.009)(330.5)^2=491.5 J

While after the collision

K_f = \frac{1}{2}(m+M)v^2 = \frac{1}{2}(0.009+1.20)(2.46)^2=3.7 J

We see that the final kinetic energy is less than the initial kinetic energy: therefore, the collision is inelastic, since part of the energy has been converted into other forms of energy (e.g. thermal energy).

c)

The impulse of the block is equal to its change in momentum, so:

I=\Delta p =p_f - p_i = (m+M)v'-(m+M)v

where

v' = 0, since the block comes to a stop

v = 2.46 m/s is the velocity of the block just after the collision

Substituting,

I=0-(0.009+1.20)(2.46)=-2.97 kg m/s

And the impulse is negative, because its direction is opposite to the direction of motion of the block (this means that the force exerted on the block, which is the force of friction, acts in the direction opposite to the motion of the block).

Learn more about kinetic energy and momentum:

brainly.com/question/6536722

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brainly.com/question/6573742

brainly.com/question/2370982

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#LearnwithBrainly

3 0
4 years ago
30.
mrs_skeptik [129]
I think the answer is B but i could be wrong
7 0
3 years ago
Read 2 more answers
planet.3.Astar is 10 light years away from the earth. Suppose it brightens up suddenly today, after how long can we see this cha
nataly862011 [7]
After 10 years, I guess.
6 0
3 years ago
Use the drop-down menus to order the steps for writing chemical formulas. Balance the charges. Identify the negative ion and cha
daser333 [38]

Answer:

The order of steps for writing a chemical formula is 3, 2, 1, 5, 4

Explanation:

Balance the charges. Identify the negative ion and charge. Identify the positive ion and charge. Use the information in the ratio to write the chemical formula. Write the ratio of ions that balances the charges.

The order of steps for writing a chemical formula from the options above is:

3.) Identify the positive in and charge.

2.) Identify the negative ion and charge.

1.) Balance the charges.

5.)Write the ratio of ions that balances the charges.

4.) Use the information in the ratio to write the chemical formula.

6 0
3 years ago
Young Jeffrey is bored, and decides to throw some things out of the window for fun. But since he is also very curious, he decide
Inga [223]

Answer:

a) Stone            v_{y} = - 7.25 ft / s ,  vₓ = 0.362 ft / s

b) tennis ball    v_{y} =  -3.16 ft / s ,   vₓ = 0.634 ft / s

c) golf ball        v_{y} = - 1,536 ft / s, vx = 0.634 ft / s

2) golf ball

Explanation:

1) The average speed is defined with the displacement interval in the given time interval

           v =( x_{f}-x₀) / Δt

let's use this expression for each object

a) Stone

  It tells us that it is released from y₀ = 10 ft and reaches the floor at

t = 0.788 s, but in the problem they tell us that the calculation is for t = 1.38 s

           v_{y} = (0-10) / 1.38

           v_{y} = - 7.25 ft / s

 in this interval a distance of x_{f} = 0.500 ft was moved away from the building (x₀ = 0 ft)

          vₓ = (0.500- 0) / 1.38

          vₓ = 0.362 ft / s

In my opinion it makes no sense to keep measuring the time after the stone has stopped.

b) tennis ball

It leaves the building at a height of y₀= 10ft and at the end of the period it is at a height of y_{f} = 5.63 ft, all this in a time of t = 0.788 + 0.591 = 1.38 s

       

the average vertical speed is

            v_{y} = (5.63 - 10) / 1.38

            v_{y} = -3.16 ft / s

for horizontal velocity the ball leaves the building xo = 0 reaches the floor

x₁ = 0.500 foot and when bouncing it travels x₂ = 0.375 foot, therefore the distance traveled

         x_{f} = x₁ + x₂

         x_{f} = 0.500 + 0.375

         x_{f} = 0.875 ft

we calculate

         vₓ = (0.875 - 0) / 1.38

         vₓ = 0.634 ft / s

c) The golf ball

the vertical displacement y₀ = 10 ft, and y_{f} = 7.88 ft

          v_{y} = (7.88 - 10) / 1.38

          v_{y} = - 1,536 ft / s

the horizontal displacement x₀ = 0 ft to the point xf = 0.875 ft

          vₓ = (0.875 -0) / 1.38

          vₓ = 0.634 ft / s

2) in this part we are asked for the instantaneous speed at the end of the time interval

a) the stone is stopped so its speed is zero

          v_{y} = vₓ = 0

b) the tennis ball

It is at its maximum height so its vertical speed is zero

        v_{y} = 0

horizontal speed does not change

          vₓ = 0.634 ft / s

c) The golf ball

they do not indicate that it is still rising. Therefore its vertical speed is greater than zero

         v_{y} > 0

horizontal speed is constant

         vₓx = 0.634 ft / s

the total velocity of the object can be found with the Pythagorean theorem

         v = √ (vₓ² + v_{y}²)

When reviewing the results, the golf ball is the one with the highest instantaneous speed at the end of the period

4 0
3 years ago
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