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jenyasd209 [6]
3 years ago
15

What is the force on a 52 coulomb charge in a field of 5 N/C

Physics
1 answer:
slega [8]3 years ago
8 0
Https://courses.physics.illinois.edu/phys102/sp2013/lectures/lecture2.pdf



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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.320 with the floor. If
mart [117]

Answer:  29.50 m

Explanation: In order to calculate the higher accelation to stop a train  without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:

f=μ*N the friction force is equal to coefficient of static friction  multiply the normal force (m*g).

f=m.a=μ*N= m*a= μ*m*g= m*a

then

a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2

With this value we can determine the short distance to stop the train

as follows:

x= vo*t- (a/2)* t^2

Vf=0= vo-a*t then t=vo/a

Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m

5 0
2 years ago
If a bottlel filled with water 25c and freezes at -5c the waters tempreture drop what is the sign of the systems q,w,ΔE
laila [671]
Triangle because h2o and celsious have yhree silibyles and the triangle has three sides
6 0
2 years ago
What is the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m? No links
myrzilka [38]

72 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 12 m

To find : -

Speed ( v ) = ?

Formula : -

v = f x λ

v

= 6 x 12

= 72 m/s

Therefore,

the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m is 72 m/s.

7 0
2 years ago
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klemol [59]

the enclosed may help. earth rotes and you and i are fixed to it. air flows it's own path ...

3 0
3 years ago
At its natural resting length, a muscle is close to its optimallength for producing force. As the muscle contracts, the maximumf
lesantik [10]

Answer:

Figure E is the correct representation of the first part of the motion. When in a hanging position from the chin-up bar, the bicep muscles are stretched beyond their normal length already. So at this point they are at the peak of their capacity and you are at rest (this corresponds to the velocity v = 0 at t = 0). On contracting the bicep muscles and pulling your whole body up, you begin to gain speed and v increases. This increase in velocity is exponential. Soon the bicep muscles contract up to 80% their normal length reducing the force they can produce to keep you rising up to zero. The velocity change happens because the body is accelerating and the muscles can still supply a net force to lift you up. The acceleration is present because of this net force. The moment this force reduces to zero, the acceleration too reduces to zero. (From Newton's second law of motion). This reduction in acceleration is responsible for the reduction of the curvature of the v curve in figure E above. The point where the velocity becomes horizontal corresponds to the point where the muscles reach their maximum contraction unit and can supply no more net force and as a result no acceleration. This further results inba constant velocity which is the flat nature of the curve seen in diagram E.

Thank you for reading.

Explanation:

5 0
3 years ago
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