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Crank
3 years ago
14

What type of isotope undergoes radioactive decay?

Chemistry
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

I picked A: one that has a nucleus with the same number of protons and neutrons

Explanation:

On edg

jeka57 [31]3 years ago
5 0

Answer:

i think the answer is a

Explanation:

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activation energy hope this is right

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Gravity.

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3 years ago
How many moles of hcl are required to neutralize aqueous solutions of these bases? 0.03 mol koh?
oksano4ka [1.4K]
 The  moles  of  HCl    are  required  to  neutralized    aqueous     solution     of  the   0.03  KoH

KOH  +  HCl  =  KCl  +   H2O


by   use  mole  ratio  between  KOH   to   HCl    which  is    1:1    the  moles    Of  HCl  is  also      0.03  moles
5 0
3 years ago
A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 295 mL of solution. How many moles o
Masja [62]

Answer:

(a) Moles of ammonium chloride = 0.243 moles

(b) Molarity_{ammonium\ chloride}=0.824\ M

(c) 60.68 mL

Explanation:

(a) Mass of ammonium chloride = 13.0 g

Molar mass of ammonium chloride = 53.491 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{13.0\ g}{53.491\ g/mol}

<u>Moles of ammonium chloride = 0.243 moles</u>

(b) Moles of ammonium chloride = 0.243 moles

Volume = 295 mL = 0.295 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{ammonium\ chloride}=\frac{0.243}{0.295}

Molarity_{ammonium\ chloride}=0.824\ M

(c) Moles of ammonium chloride = 0.0500 moles

Volume = ?

Molarity = 0.824 M

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

0.824\ M=\frac{0.0500}{Volume}

<u>Volume = 0.05 / 0.824 L = 0.06068 L = 60.68 mL</u>

6 0
3 years ago
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