Answer:
The answer to your question is distance between these electrons
= 1.386 x 10⁻¹⁴ m
Explanation:
Data
Force = F = 1.2 N
distance = d = ?
charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C
K = 8.987 x 10⁹ Nm²/C²
Formula
-To solve this problem use the Coulomb's equation
F = kq₁q₂ / r²
-Solve for r²
r² = kq₁q₂ / F
-Substitution
r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2
- Simplification
r² = 2.306 x 10⁻²⁸ / 1.2
r² = 1.922 x 10⁻²⁸
-Result
r = 1.386 x 10⁻¹⁴ m
The force exerted by one plate for two parallel plates arrangement is F = QE/2.
<h3>
Force one plate exerts on the other</h3>
The force exerted by one plate for two parallel plates arrangement is given as follows;
F = QE/2
where;
- Q is the charge on one plates
- E is the electric field due to the charge
- F is force exerted by one plate
Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.
Learn more about force between parallel plates here: brainly.com/question/13590045
Answer:
The rate of current change in the circuit is
Explanation:
From the question we are told that
The capacitor has a value
The inductor has a value
The capacitors voltage is at t = 0s
The new capacitor voltage is
Generally when the switch is closed the potential across the inductor is equal to the potential across the capacitor
So for the inductor
rate of current change is given as
Where is the voltage across the inductor.
Substituting value
Answer:
M = 3.485 kg
m = 1.605 kg
Explanation:
F = 0.98 x 10^-8 N
r = 19.5 cm = 0.195 m
M + m = 5.09 kg ...... (1)
By use of Newton's gravitational law
F = G m1 m2 / r^2
0.98 x 10^-8 = 6.67 x 10^-11 x M x m / (0.195)^2
M x m = 5.59
M - m = 1.88 .........(2)
By solving the equation (1) and equation (20, we get
M = 3.485 kg
m = 1.605 kg