Answer:
 Range of arrow = 225.09 meter
 Final horizontal velocity = 34.47 m/s
Explanation:
 We have equation of motion  , where u is the initial velocity, t is the time taken, a is the acceleration and s is the displacement.
, where u is the initial velocity, t is the time taken, a is the acceleration and s is the displacement.
 Considering the vertical motion of arrow ( up direction as positive)
    We have u = 45 sin40 = 28.93 m/s, s = -20 m, a = acceleration due to gravity =  .
.
    
    t = 6.53 seconds or t = -0.63 seconds
    So time = 6.53 seconds.
 Considering the horizontal motion of arrow
    u = 45 cos 40 = 34.47 m/s, t = 6.53 s, a = 
    
 So range of arrow = 225.09 meter
 Horizontal velocity will not change , final horizontal velocity = 34.47 m/s.