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iragen [17]
3 years ago
9

A wire of Nichrome (a nickel-chromium-iron alloy commonly used in heating elements) is 1.3 m long and 1.6 mm2 in cross-sectional

area. It carries a current of 3.2 A when a 2.0 V potential difference is applied between its ends. Calculate the conductivity σ of Nichrome. /Ω · m
Physics
1 answer:
fredd [130]3 years ago
5 0

Answer: 1.3 *10^6 Ω*m

Explanation: In order to explain this problem we have to use the following expression for the resistence:

R=L/(σ*A) where L and A are the length and teh area for the wire, respectively. σ is the conductivity of teh Nichrome.

Then, from mteh OHM law we have V=R*I so R=V/I=2/3.2=0.625 Ω

Finally we have:

σ=L/(R*A)=1.3/(0.625*1.6*10^-6)=1.3*10^6 Ω*m

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<h2>Resultant is 235.54 pounds at an angle 44.16° to X axis.</h2>

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\texttt{Magnitude = }\sqrt{168.97^2+164.10^2}\\\\\texttt{Magnitude = }235.54pounds\\\\\texttt{Angle = }tan^{-1}\left ( \frac{164.10}{168.97}\right )\\\\\texttt{Angle = }44.16^0

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