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seraphim [82]
3 years ago
10

Can someone help me?!!!!!

Physics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

7 units, north

Explanation:

This is a problem of vector subtraction. We have:

- Vector A: magnitude 2 units, direction to the north

- Vector B: magnitude 5 units, direction to the south

If we take the north as positive direction, we can write

A = +2\\B=-5

Since we want to find A-B (vector subtraction), we have to change the sign of B, so we find:

A-B=+2-(-5))=+2+5=+7

And the positive sign means the direction is north.

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When the current in a toroidal solenoid is changing at a rate of 0.0240 A/s , the magnitude of the induced emf is 12.4 mV . When
Gemiola [76]

Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

Rate of change of current, \dfrac{dI}{dt}=0.0240\ A/s

Induced emf, \epsilon=12.4\ mV=12.4\times 10^{-3}\ V

Current, I = 1.5 A

Magnetic flux, \phi=0.00338\ Wb

The induced emf through the solenoid is given by :

\epsilon=L\dfrac{dI}{dt}

or

L=\dfrac{\epsilon}{(di/dt)}........(1)

The self inductance of the solenoid is given by :

L=\dfrac{N\phi}{I}.........(2)

From equation (1) and (2) we get :

\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}

N is the number of turns in the solenoid

N=\dfrac{\epsilon I}{\phi (dI/dt)}

N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}

N = 229.28 turns

or

N = 230 turns

So, the number of turns in the solenoid is 230. Hence, this is the required solution.

3 0
3 years ago
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.00
saul85 [17]

Answer:

this is the answer according to my calculations

Explanation:

0.001.9

5 0
3 years ago
An all-electric car (not a hybrid) is designed to run from a bank of 12.0 V batteries with total energy storage of 2.30 ✕ 107 J.
AnnyKZ [126]

Answer:

a) I=733.33\ A

b) d=52272.7273\ m

c) d'=51948.0519\ m

Explanation:

Given:

  • voltage of the battery, V=12\ V
  • energy storage capacity of the battery, E=2.3\times 10^7\ J
  • speed of the car, v=20\ m.s^{-1}

a)

power drawn by the car, P=8.8\ kW

<u>Now the Current delivered to the motor:</u>

we the relation between the power and electrical current,

P=V.I

8800=12\times I

I=733.33\ A

b)

<u>Distance travelled before battery is out of juice:</u>

we first find the time before the battery runs out,

t=\frac{E}{P}

t=\frac{2.3\times 10^7}{8800}

t=2613.636\ s

Now the distance:

d=v.t

d=20\times 2613.636

d=52272.7273\ m

c)

When the head light of 55 W power is kept on while moving then the power   consumption of the car is:

P'=P+55

P'=8800+55

P'=8855\ W

<u>Now the time of operation of the car:</u>

t'=\frac{E}{P'}

t'=\frac{2.3\times 10^7}{8855}

t'=2597.4026\ s

<u>Now the distance travelled:</u>

d'=v.t'

d'=20\times 2597.4025

d'=51948.0519\ m

5 0
3 years ago
A car is driving at 85 km/h and the driver spots a stop sign ahead. What coefficient of friction is needed to stop the car at th
almond37 [142]

Answer:

μ = 0.0315

Explanation:

Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)

N = m*g (1)

The friction force is equal to the product of the normal force by the coefficient of friction.

F = μ*N (2)

This way replacing 1 in 2, we have:

F = μ*m*g (2)

Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.

\frac{1}{2} *m*v_{i}^{2}-(F*d)=  \frac{1}{2} *m*v_{f}^{2}

where:

vf = final velocity = 0

vi = initial velocity = 85 [km/h] = 23.61 [m/s]

d = displacement = 900 [m]

F = friction force [N]

The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.

Now replacing:

(1/2)*m*(23.61)^2 = μ*m*g*d

0.5*(23.61)^2 = μ*9,81*900

μ = 0.0315

5 0
3 years ago
Next weekend you are going to Eleanor Rigby’s house to fix her grandfather clock that is a bit slow. Based on what you have lear
Bumek [7]

Answer:

By pushing the pendulum Bob up so it moves faster

Explanation:

In pendulum physics the length of the pendulum Bob determines the speed of the clock. So since the grandfather's clock is slow it means the Bob is has moved down so to move it up you have to achieve this by adjusting the but upwards thereby making the clock move faster.

8 0
3 years ago
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