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seraphim [82]
3 years ago
10

Can someone help me?!!!!!

Physics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

7 units, north

Explanation:

This is a problem of vector subtraction. We have:

- Vector A: magnitude 2 units, direction to the north

- Vector B: magnitude 5 units, direction to the south

If we take the north as positive direction, we can write

A = +2\\B=-5

Since we want to find A-B (vector subtraction), we have to change the sign of B, so we find:

A-B=+2-(-5))=+2+5=+7

And the positive sign means the direction is north.

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Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
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Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

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So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

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A ball is dropped from a building taking 3sec to fall to the ground. Calculate:
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Answer:

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Explanation:

Data:

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==================================================================

Final Velocity

Use formula:

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Replace:

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Multiply:

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==================================================================

Height

Use formula:

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Replace:

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Multiply time squared:

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It divides:

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The final velocity is <u>29.4 meters per seconds.</u>

How high is the building?

The height of the building is <u>44.1 meters.</u>

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