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Explanation:
The partial pressure of an individual gas is equal to the total pressure of the mixture multiplied by the mole fraction of the gas.
Total pressure = 2atm
Mole Fraction = number of moles / total number of moles
Neon
Mole Fraction = 4.46 / 7.35 = 0.607
Partial Pressure = 0.607 * 2 = 1.214 atm
Argon
Mole Fraction = 0.74 / 7.35 = 0.101
Partial Pressure = 0.101 * 2 = 0.202 atm
Xenon
Mole Fraction = 2.15 / 7.35 = 0.293
Partial Pressure = 0.293 * 2 = 0.586 atm
Thank you for posting your question here at brainly. I hope the answer will help you. The number of moles of gas were produced the answer will be 0.0023 mol.
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Answer:
121.78 g
Explanation:
You multiply the mols by the grams in one mol.
First we dissociate the salt
NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]
note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.
OCl⁻ + H₂O ⇄ OH⁻ + HOCL
<span>Ka for HOCl = 3.0x10^-8, therefore
Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
= 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
= 3.3 × 10⁻⁷
</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]
convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴
set up equib table
OCl⁻ + H₂O ⇄ OH⁻ + HOCl
ST x 0 0
+Δ -1.995 × 10⁻⁴ +1.995 × 10⁻⁴ +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
EQ: x -1.995 × 10⁻⁴ 1.995 × 10⁻⁴ 1.995 × 10⁻⁴
Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]
The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M
