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GalinKa [24]
3 years ago
12

How many molecules are in 85 grams of Silver?

Chemistry
1 answer:
densk [106]3 years ago
8 0

Answer:

3.0 × 10

3.0 \times  {10}^{23}

molecules

Explanation:

there are many molecules

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NaCl + H2SO4 ---&gt; Na2SO4 + HCl<br> Balance the double replacement chemical reaction.
vlada-n [284]

Answer:

2NaCl + H2SO4 ----> Na2SO4 + 2HCl

Explanation:

4 0
3 years ago
Read 2 more answers
Although Plato and Aristotle disagreed with democritus what did his theory suggest was true about all matter?
Gnesinka [82]
Democritus believed that the universe was composed of atoms, correctly, of course. However, at the time, Plato's and Aristotle's hypothesi were just as valid because everyone was a philosopher. There were no scientists back then.
6 0
3 years ago
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On the first day of your new job as a chemist, you are given a bottle of magnesium sulfate and asked to make 30 mL of 0.3 M MgSO
Lady bird [3.3K]

Answer:

The answer to your question is 15500 mg of MgSO₄ 7H₂O

Explanation:

Data

Volume = 30 ml

Concentration = 0.3 M

Formula MgSO4∗7H2O

Process

1.- Calculate the number of moles needed

 Molarity = moles / volume

Solve for moles

 moles = Molarity x volume

Substitution

 moles = 0.3 x 0.03 l

 moles = 0.009 moles of MgSO₄

2.- Calculate the molecular mass of MgSO4∗7H2O

molecular mass = 24 + 32 + 64 + 14 + 112

                           = 246 g

3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7

4.- Calculate the amount of MgSO4∗7H2O

    0.009 mol of MgSO4 \frac{7 MgSO4 7H2O}{1 mol MgSO4} \frac{246 g MgSO4 7H2O}{1 mol MgSO4 7H2O}

Simplification

   15.5 g = 15500 mg

5 0
3 years ago
Help me with this one please!
Allisa [31]

Answer:

sorry i dont know

Explanation:

3 0
2 years ago
Calculate the standard cell potential at 25 ∘c for the reaction x(s)+2y+(aq)→x2+(aq)+2y(s) where δh∘ = -793 kj and δs∘ = -319 j/
QveST [7]
First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
        = - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts   
 
5 0
3 years ago
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