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mote1985 [20]
3 years ago
8

What standard feature is on all circular saws?

Engineering
1 answer:
PtichkaEL [24]3 years ago
4 0

What standard feature is on all circular saws?

4. All of the above

You might be interested in
The speed of a vehicle is reduced with a constant acceleration from 72km/h to 18
Radda [10]

Answer:

The correct answer will be "1477.84 N".

Explanation:

Given that,

Mass,

m = 1.6 mg

or,

   = 1600 kg

Initial velocity,

u = 72 km/h

  = 72\times \frac{5}{18} \ m/s

  = 20 \ m/s

Final velocity,

v = 18 km/h

  = 18\times \frac{5}{18}

  = 5 \ m/s

Covered distance,

s = 250 m

By using the below relation, we get

⇒  v^2=u^2+2as

On putting the values, we get

⇒  (5)^2=(20)^2+2\times a\times 250

⇒      a=-0.75 \ m/s^2 (shows the deceleration)

Slope will be given as 1 in 25, then

⇒  Sin \theta=\frac{1}{25}

           \theta=2.3^{\circ}

hence,

As we know,

⇒  \Sigma F=ma

or,

⇒  Braking \ force+350-mgSin\theta=ma

⇒  Braking \ force=ma+mgSin\theta-350

On substituting all the values, we get

⇒                           =1600(0.75+1600\times 9.81 Sin(2.3^{\circ})-350

⇒                           =1477.84 \ N

7 0
3 years ago
Determine linear atomic density along [001] direction of a FCC unit cell with lattice constant a (cube edge length).
SIZIF [17.4K]

Answer:

LD=\dfrac{0.5}{ a}

Explanation:

Given that

Unit cell is in FCC

Here given direction is not clear visible so we take direction [001].

We know that linear density(LD) given as

LD=\dfrac{Number\ of\ atoms\ in\ the\ direction\ vector}{d_{[001]}}

So the number of atom will be 1/2 in direction  [001]

In FCC

a=2\sqrt2 \ r

LD=\dfrac{0.5}{ a}

LD=\dfrac{1}{2\sqrt2 \ r}

6 0
3 years ago
What steel type and ASTM designation is preferred for W-shapes?
Ulleksa [173]

Answer:

The preferred steel type for W-shapes is structural steel and the its preferred ASTM designation is ASTM A992.

Explanation:

The ASTM A992 is a structural steel and it's the most available for w-shapes; besides its availabilty, its ductility improvements makes it the preferred choice; other common designations for this shapes are ASTM A572 Grade 50,0r ASTM A36, but this designations aren't as available as ASTM A992, and it has to be confirmed prior to their specification.

3 0
4 years ago
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
gladu [14]

Answer:

F(x) = 0           ;  x < 0

         0.064   ;  0 ≤ x < 1

         0.352   ;  1 ≤ x < 2

         0.784   ;  2 ≤ x < 3

            1        ;    x ≥ 3

Explanation:

Each wafer is classified as pass or fail.

The wafers are independent.

Then, we can modelate X : ''Number of wafers that pass the test'' as a Binomial random variable.

X ~ Bi(n,p)

Where n = 3 and p = 0.6 is the success probability

The probatility function is given by :

P(X=x)=f(x)=nCx.p^{x}.(1-p)^{n-x}

Where nCx is the combinatorial number

nCx=\frac{n!}{x!(n-x)!}

Let's calculate f(x) :

f(0)=3C0.(0.6^{0}).(0.4^{3})=0.4^{3}=0.064

f(1)=3C1.(0.6^{1}).(0.4^{2})=0.288

f(2)=3C2.(0.6^{2}).(0.4^{1})=0.432

f(3)=3C3.(0.6^{3}).(0.4^{0})=0.6^{3}=0.216

For the cumulative distribution function that we are looking for :

P(X\leq x)=F(x)

F(0)=f(0)\\F(1)=f(0)+f(1)\\F(2)=f(0)+f(1)+f(2)\\F(3)=f(0)+f(1)+f(2)+f(3)=1

F(0)=0.064\\F(1)=0.064+0.288=0.352\\F(2)=0.064+0.288+0.432=0.784\\F(3)=0.064+0.288+0.432+0.216=1

The cumulative distribution function for X is :

F(x) = 0           ;  x < 0

         0.064   ;  0 ≤ x < 1

         0.352   ;  1 ≤ x < 2

         0.784   ;  2 ≤ x < 3

            1        ;    x ≥ 3

5 0
3 years ago
Answer true or false 3.Individual people decide what will be produced in a command<br> oconomy
Pie

Answer:

False

Explanation:

The government decides the productions.

7 0
4 years ago
Read 2 more answers
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