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3 years ago

Which substance will form a solution when mixed with liquid benzene (c6h6)

Chemistry

2 answers:

Zina [86]3 years ago

4 0

Answer:

Benzene will form a solution with hexane. c6h14

shtirl [24]3 years ago

4 0

Answer: $I_{2} (l)$

Explanation: Because C 6 H 6 is nonpolar substance and I 2 is also nonpolar compound

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Please do 1-5! giving 5 stars and thanks if right!

Burka [1]

Answer:

1. 100 centimeters

2. 1 gram

3. 1000 meters

4. 10 millimeters

5. 1000 grams

6 0

3 years ago

Ammonium perchlorate (NH4ClO4) is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitroge

Temka [501]

Answer:

1.08 grams of nitrogen

Explanation:

Thermally ammonium perchlorate dissociate as shown in figure.

Thus as per equation two moles of ammonium perchlorate will give four moles of water, two moles of oxygen, one mole of chlorine and one mole of nitrogen,

The molar mass of ammonium perchlorate = 117.5g/mol

Two moles of ammonium perchlorate = 2X 117.5 = 234 g

The molar mass of nitrogen = 28g

thus 234 grams of ammonium perchlorate will give 28 grams of nitrogen

Hence 9 grams of ammonium perchlorate will give 1.08 grams of nitrogen

6 0

3 years ago

Hello! So I need help with these neutralization reactions and its fill in the blank. The question asks,

Likurg_2 [28]

The balanced equation for the neutralization reactions is as below.

<h3>Balancing chemical reaction equations</h3>

In order for chemical equations to be balanced, the number of atoms of each element before and after the reaction must be equal.

Thus:

$HBr + KOH --- > KBr + H_2O$
$3HF + Fe(OH)_3 --- > 3 H_2O + FeF_3$
$2HCl + Ca(OH)_2 --- > CaCl_2 + 2H_2O$

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

5 0

2 years ago

Evaporate minerals, or "salts," include halite, anhydrite, and ______.

pav-90 [236]

B is the correct answer! I learned this in class last week :)

5 0

4 years ago

Read 2 more answers

If the reaction was reversed and we wanted to produce as much NaN3, in grams, as possible from 30.0 g of N2 and 20.0 g of Na, wh

Valentin [98]

Answer:

N₂

Explanation:

Sodium is a larger molecule with a much higher molecular weight. However, 20g of N₂ would be a smaller amount of molecules than 20g of sodium due to how there are multiple nitrogen molecules.

2/3 * given mass of N₂ = mass of N₃

N₃ (Azide ion) given mass = 20g

Na = 20g

Masses of chemicals are equal

Na = 22.990g/mol

20g/22.990g/mol = 0.8699mol of Na

N₃ = 20g

N₃ = N g/mol x 3

N = 14.007 g/mol

14.007 x 3 = 42.021 g/mol

N₃ = 42.021g/mol

20g/42.021g/mol = 0.4759 mol of N₃

Notice how there are fewer moles of the Azide ion than the Sodium.

0.4759 moles of NaN₃ is produced

combine molecular weights:

42.021 + 22.990 = 65.011 g/mol

multiply by amount of moles of the limiting reactant:

0.4759 mol *65.011 = 30.942 g

Also, here is the balanced equation:

3N₂ + 2Na = 2NaN₃

The results are the same as the balanced equation.

4 0

3 years ago