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3 years ago

How does math relate to electrons and ion formation?

Chemistry

2 answers:

irinina [24]3 years ago

7 0

1) Preliminar explanation:

Atoms are neutral spieces: they have the same number of positive charges (protons inside the nucleous) as of negative charges (electrons around the nucleus).

Ions are formed by the gain or loss of electrons.

Positive ions are formed when neutral the atoms lose electrons, and negative ions are formed when neutral atoms gain electrons. Only the elctrons are gain or loss in ions formation (the number of protons remain unchanged).

2) Conclusion (answer)

Therefore, mathematically an ion is the result of adding or subtracting electrons to an atom, creating an imbalance of charge, positve when the atom ends up with less electrons than protons (loss of electrons) or negative when the atoms ends up with more electrons than protons (gain of electrons).

Vlad1618 [11]3 years ago

4 0

There are calculations that chart where an electron will be in it's orbit, which I turn influences whether or not it will form an ionic bond and the new orbitals if it does.

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Is LiOH soluble or insoluble?

riadik2000 [5.3K]

LiOH is soluble. Na2CO3 is soluble. Cu(OH)2 is insoluble.

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3 years ago

Which of the following occurs when sodium and chlorine bond together to form sodium

Mumz [18]

(a) chlorine gains an electron from a sodium atom

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2 years ago

Perform each of the following unit conversions using the conversion factors given below:

andrezito [222]

1. 1086.04 mmHg

2.70.213 mmHg

3. 95.954 kPa

<h3>Further explanation</h3>

Pressure (P) is the force applied per unit area

Can be formulated :

$\tt P=\dfrac{F}{A}$

P = pressure (SI=Pascal(Pa))

F= force applied (N)

A=area(m²)

The unit of pressure can be expressed in atm, mmHg, or Pascal

$\tt 1.\dfrac{1.429}{1}\times 760=1086.04~mmHg$

$\tt 2)~9,361~Pa=9.361~kPa=\dfrac{9.361}{101.325}\times 760=70.213~mmHg$

$\tt 3)\dfrac{725}{760}\times 1=0.947~atm=\dfrac{0.947}{1}\times 101.325=95.954~kPa$

4 0

2 years ago

Read 2 more answers

Calculate the frequency of the n=2 line in the lyman series of hydrogen

Alona [7]

Answer:

Approximately $2.47\times 10^{15}\; \rm Hz$ .

Explanation:

The Lyman Series of a hydrogen atom are due to electron transitions from energy levels $n \ge 2$ to the ground state where $n = 1$ . In this case, the electron responsible for the line started at $n = 2$ and transitioned to

A hydrogen atom contains only one electron. As a result, Bohr Model provides a good estimate of that electron's energy at different levels.

In Bohr's Model, the equation for an electron at energy level $n$ (

$\displaystyle - \frac{k\, Z^2}{n^2}$ (note the negative sign in front of the fraction,)

where

$k = 2.179 \times 10^{-18}\; \rm J$ is a constant.

$Z$ is the atomic number of that atom. $Z = 1$ for hydrogen.
$n$ is the energy level of that electron.

The electron that produced the $n = 2$ line was initially at the

$\begin{aligned} &E_{n = 2} \cr &= -\frac{k\, Z^2}{n^2} \cr &= -\frac{2.179 \times 10^{-18} \times 1}{2^2} \cr & \approx -5.4475\times 10^{-19}\; \rm J\end{aligned}$ .

The electron would then transit to energy level $n = 1$ . Its energy would become:

$\begin{aligned} &E_{n = 1} \cr &= -\frac{k\, Z^2}{n^2} \cr &= -\frac{2.179 \times 10^{-18} \times 1}{1^2} \cr & \approx -2.179 \times 10^{-18} \; \rm J\end{aligned}$ .

The energy change would be equal to

$\begin{aligned}&\text{Initial Energy} - \text{Final Energy} \cr &= E_{n = 2} - E_{n = 1} \cr &= -5.4475 \times 10^{-19} - \left(-2.179 \times 10^{-18}\right) \cr & \approx 1.63425\times 10^{-18}\; \rm J \end{aligned}$ .

That would be the energy of a photon in that $n = 2$ spectrum line. Planck constant $h$ relates the frequency of a photon to its energy:

$E = h \cdot f$ , where

$E$ is the energy of the photon.
$h \approx 6.62607015\times 10^{-34}\; \rm J \cdot s$ is the Planck constant.
$f$ is the frequency of that photon.

In this case, $E \approx 1.63425 \times 10^{-18}\; \rm J$ . Hence,

$\begin{aligned} f &= \frac{E}{h} \cr &\approx \frac{1.63425\times 10^{-18}}{6.62607015\times 10^{-34}} \cr & \approx 2.47 \times 10^{15}\; \rm s^{-1}\end{aligned}$ .

Note that $1 \; \rm Hz = 1 \; \rm s^{-1}$ .

6 0

3 years ago

An element has 13 protons in its nucleus. What is its atomic number?

Dafna11 [192]

Answer:

The answer is 13.

Explanation:

In an element, proton number is also define as atomic number. So if the element has 13 protons, it's atomic number will be 13.

6 0

3 years ago

Read 2 more answers