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navik [9.2K]
3 years ago
7

How does math relate to electrons and ion formation?

Chemistry
2 answers:
irinina [24]3 years ago
7 0

1) Preliminar explanation:

Atoms are neutral spieces: they have the same number of positive charges (protons inside the nucleous) as of negative charges (electrons around the nucleus).

Ions are formed by the gain or loss of electrons.

Positive ions are formed when neutral the atoms lose electrons, and negative ions are formed when neutral atoms gain electrons. Only the elctrons are gain or loss in ions formation (the number of protons remain unchanged).

2) Conclusion (answer)

Therefore, mathematically an ion is the result of adding or subtracting electrons to an atom, creating an imbalance of charge, positve when the atom ends up with less electrons than protons (loss of electrons) or negative when the atoms ends up with more electrons than protons (gain of electrons).

Vlad1618 [11]3 years ago
4 0
There are calculations that chart where an electron will be in it's orbit, which I turn influences whether or not it will form an ionic bond and the new orbitals if it does.
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Which element in Group 17 is the most active nonmetal? (1) Br (2) I (3) Cl (4) F
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7 0
1 year ago
The diameter of the He He atom is approximately 0.10 nm nm . Calculate the density of the He atom in g/cm 3 g/cm3 (assuming that
Sladkaya [172]

Answer:

Density of the He atom = 12.69 g/cm³

Explanation:

From the information given:

Since 1 mole of an atom = 6.022x 10²³ atoms)

1 atom of He = 1  \ atom \times  (\dfrac{1  \ mole}{  6.022 \times  10^{23}  \ atoms}) \times ( \dfrac{4.003 \ grams}{  1  \ mole})

=6.647 \times  10^{-24} \  grams

The volume can be determined as  folows:

since the diameter of the He atom is approximately 0.10 nm

the radius of the He = \dfrac{0.10}{2} = 0.05 nm

Converting it into cm, we have:

0.05 nm \times  \dfrac{10^{-9} \  meters}{ 1  nm} \times \dfrac{ 1 cm }{10^{-2} \ meters}

=5 \times  10^{-9}  \ cm

Assuming that it is a sphere, the volume of a sphere is

= \dfrac{4}{3}\pi r^3

= \dfrac{4}{3}\pi  \times (5\times 10^{-9})^3

= 5.236 \times 10^{-25} \ cm^3

Finally, the density can be calcuated by using the formula :

Density = \dfrac{mass}{volume}

D =  \dfrac{6.647 \times  10^{-24} \  grams }{ 5.236 \times 10^{-25} \  cm^3}

D = 12.69 g/cm³

Density of the He atom = 12.69 g/cm³

4 0
3 years ago
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