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3 years ago

Generators?

Physics

1 answer:

kodGreya [7K]3 years ago

8 0

Answer:

A)take motion and induce a current

Explanation:

i hope it will be helpful

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When a sound source is moving toward the observer, the observer will hear a higher pitch. This is due to

Goryan [66]

Number one a and b are automatically out if you decrease the pitch or frequency you wont hear it louder it does not add up ok?
number 2 the answer would be C the higher the frequency the higher the pitch the lower the frequency the lower the pitch this just comes back to common sense. for example you cant decrease the frequency and than expect a louder pitch its like saying I am going to smash the key on this piano with all my strength and it will make a small very low pitch sound you get what I mean so your answer would indeed be C.

5 0

3 years ago

Read 2 more answers

When you have a pot of water on the stove, heat is transferred to the water. Describe the behavior of the water molecules and ho

Digiron [165]

The hotter molecules become, the faster they move around. The colder they are, the more slow and lethargic they are

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3 years ago

A vessel of 0.25 m3 capacity is filled with saturated steam at 1500 kPa. If the vessel is cooled until 25% of the steam has cond

soldier1979 [14.2K]

Answer:

the final pressure is P=353.5 kPa and the heat lost by the system (heat transferred) is Q= -3614.7327 kJ ( negative sign means heat outflow)

Explanation:

since the steam is at saturated state at 1500 kPa , from tables of saturated steam

at P= 1500 kPa → specific volume v= 0.13225 m³/kg , ug=2593.3 kJ/kg

thus

m = V/v = 0.25 m³ / 0.13225 m³/kg = 1.89 kg

for condensation until 25% of steam, then mass of steam is

mg₂ = 0.25* 1.89 kg = 0.4725 kg

if we neglect the volume occupied by the liquid , then the steam occupies

v₂ = V/m = 0.25 m³ / 0.4725 kg =0.529 m³/kg

returning to the saturated steam table

at v₂=0.529 m³/kg → 353.5 kPa , uL₂= 584.1585 kJ/kg , ug₂= 2548.4965 kJ/kg

then from the first law of thermodynamics

ΔU= Q - W , but since V=constant , dV=0 and W=∫PdV =0

Q= ΔU

Q= (mg₂*ug₂+ml₂*uL₂) - (m*ug) = 1.89 kg* (0.25*2548.4965 kJ/kg + 0.75*584.1585 kJ/kg - 2593.3 kJ/kg) = -3614.7327 kJ

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3 years ago

A car is moving initially at 30 m/s comes gradually at stop at 900 m . What is acceleration of the car ?

ziro4ka [17]

The acceleration of the car is 0.5 meters per seconds square.

Given the following data:

Initial velocity, U = 30 m/s

Distance, S = 900 meters

Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.

To find the acceleration of the car, we would use the third equation of motion;

Mathematically, the third equation of motion is given by the formula;

$V^2 = U^2 - 2aS\\\\0 = 30^2 - 2a(900)\\\\0 = 900 - 1800a\\\\1800a = 900\\\\a = \frac{900}{1800}$

Acceleration, a = 0.5 $m/s^2$

Therefore, the acceleration of the car is 0.5 meters per seconds square.