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2 years ago

Generators?

Physics

1 answer:

kodGreya [7K]2 years ago

8 0

Answer:

A)take motion and induce a current

Explanation:

i hope it will be helpful

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A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration

Rufina [12.5K]

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

$F_f = \mu N$

Where,

$\mu =$ Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

$m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\$

By condition of Balance the friction force must be equal to the total net force, that is to say

$F_{net} = F_f$

$m_{total}a = \mu m_hg$

$(m_h+m_c)a = \mu*m_h*g$

Re-arrange to find acceleration,

$a= \frac{\mu*m_h*g}{(m_h+m_c)}$

$a = \frac{0.894*242*9.8}{(242+224)}$

$a = 4.54 m/s^2$

Therefore the acceleration the horse can give is $4.54m/s^2$

3 0

2 years ago

Estimate the electric field at a point 2.40 cm perpendicular to the midpoint of a uniformly charged 2.00-m-long thin wire carryi

nadya68 [22]

Answer:

$E = 1.85*10^{12}\frac{N}{C}$

Explanation:

Hi!

The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.

The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction, and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:

$E = \frac{\lambda}{2\pi \epsilon_0 r}\\\lambda=\text{charge per unit length}=\frac{4.95 \mu C}{2 m} = 2.475 \frac{C}{m}\\r=\text{perpendicular distance to wire}\\\epsilon_0=8.85*10^{-12}\frac{C^2}{Nm^2}$

Then the electric field at the point of interest is estimated as:

$E = \frac{\22.475}{2\pi*( 8.85*10^{-12})*(2.4*10^{-2})}\frac{N}{C}=1.85*10^{12}\frac{N}{C}$

6 0

3 years ago

A charge of 19 nC is uniformly distributed along a straight rod of length 15 m that is bent into a circular arc with a radius of

Salsk061 [2.6K]

Answer:

The magnitude of the electric field at the center of curvature of the arc is 3.87 N/C

Explanation:

Please see the attachments below

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2 years ago

Must two quantities have the same dimensions if you are multiplying them?

vlabodo [156]

No, to multiply or divide. Yes, to add or subtract.

7 0

3 years ago

Oz discusses his work in the circus in the wonderful wizard of oz. he tells them about the ventriloquists in the circus. what is

iren [92.7K]

a person who alters their voice to make it seem as though the sound is coming from somewhere else, typically a puppet is a ventriloquist.

<h3>Which ventriloquist was the best?</h3>

Jimmy Nelson, an American ventriloquist who performed on television in the 1950s and 1960s, was born on December 15, 1928.

<h3>What makes it a ventriloquist?</h3>

The incorrect but long-held notion that the voice came from the stomach is explained by the word ventriloquism's Latin roots, ventri (belly) and loquor (to talk).

<h3>Why is a ventriloquist good?</h3>

Making your puppet seem lifelike and honing your voice are essential for becoming a competent ventriloquist. To divert attention from yourself, keep moving the body, arms, and head of the creature. To assist people forget that your puppet is actually you, try to make the character as different from you as you can.

learn more about ventriloquist here

<u>brainly.com/question/15900836</u>

#SPJ4

7 0

1 year ago