Answer:
12.34 amu
Explanation:
Let the 1st isotope be A
Let the 2nd isotope be B
Let the 3rd isotope be C
From the question given above, the following data were obtained:
1st Isotope (A):
Mass of A = 12.32 amu
Abundance (A%) = 19.5%
2nd isotope (B):
Mass of B = 13.08 amu
Abundance (B%) = 26.23%
3rd isotope (C):
Mass of C = 11.99 amu
Abundance (C%) = 54.27%
Atomic mass of X =?
The atomic mass of the element X can be obtained as follow:
Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
= [(12.32 × 19.5)/100] + [(13.08 × 26.23)/100] + [(11.99 × 54.27)/100]
= 2.402 + 3.431 + 6.507
= 12.34 amu
Thus, the atomic mass of the element X is 12.34 amu
Answers:
Atomic number = 63
Mass = 150.919 a.m.u
Nuclear symbol = ¹⁵¹Eu₆₃
Explanation:
Europium (Eu) is a member of lanthanide series in periodic table. these are radioactive elements that emits radiations continuously. these elements are also called rare earth element due to their rare existent.
Europium (Eu) has two naturally occurring isotopes as follow,
1) Eu¹⁵² with 52.19 % abundance.
2) Eu¹⁵¹ with 47.81 % abundance.
The stored energy of an object is kinetic energy
