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DochEvi [55]
3 years ago
8

The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below.

Chemistry
2 answers:
lesantik [10]3 years ago
8 0
Remark
The balance numbers in front of Ag and AgNO3 are both 2. That number is in moles.

Rule: if the moles are the same in the equation, then whatever you are given for one, will be the same for the other. So you have 0.854 moles of Ag. You will also have 0.854 moles of AgNO3 

Answer: 0.854 <<<<<
Snezhnost [94]3 years ago
4 0

<u>Answer:</u> Moles of AgNO_3 that must be reacted are 0.854 moles.

<u>Explanation:</u>

For the given chemical reaction, the equation follows:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

By Stoichiometry of the reaction:

2 moles of silver are produced when 2 moles of silver nitrate is reacted.

So, 0.854 moles of silver is formed when = \frac{2}{2}\times 0.854=0.854moles of silver nitrate is reacted.

Thus, moles of AgNO_3 that must be reacted are 0.854 moles.

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Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
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Answer:

The correct answer is 2.75 grams of HCl.

Explanation:

The given balanced equation is:  

CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams

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Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
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Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

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Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

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Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

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