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slavikrds [6]
3 years ago
8

Solve 2x2 + 12x − 14 = 0 by completing the square, options: A. 2(x + 6)2 = 26; x = −6 + square root 13, x = −6 − square root 13

B. 2(x + 6)2 = 20; x = −6 + square root 20, x = −6 − square root 20 C. 2(x + 3)2 = 32; x = 1, x = −7 D. 2(x + 3)2 = 32; x = 13, x = 19
Mathematics
2 answers:
musickatia [10]3 years ago
8 0
I just solved this one
anothe way is undistribute the 2 first and move -14 to side
2(x^2+6x)-14=0
comlete the squer inside and add negative
2(x^2+6x+9-9)-14=0
factor perfect square
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
add 32 both sides
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt both sides
x+3=+/-4
minus 3
x=-4-3 or 4-3
x=1 or -7

answer is C

bogdanovich [222]3 years ago
7 0

Answer:

the answer is c: 2(x + 3)2 = 32; x = 1, x = −7

Step-by-step explanation:

I took the test

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3 0
2 years ago
A lottery consists of one $2000 winner, three $500 winners, and ten $100 winners. a total of 1000 tickets are sold for $10 each.
Semenov [28]

Answer: -5.5

 

WOKINGS

Given that the lottery has the following number of winners:

One $2000 winner

Three $500 winners

Ten $100 winners

 

Also Given,

A total of 1000 tickets are sold

Each ticket costs $10

 

The expected winning for a person purchasing one ticket is the sum of the products of the gain/loss and their corresponding probability.

 

There is one $2000 winner

There are 1000 tickets

The probability of winning $2000

= 1/1000

= .001

There are three $500 winners

There are 1000 tickets

The probability of winning $500

= 3/1000

= .003

 


There are ten $100 winners

There are 1000 tickets

The probability of winning $100

= 10/1000

= .01

 

Since each ticket costs $10

Everyone who buys a ticket automatically loses $10.

Therefore, the probability of losing $10 is 1

 

Now to calculate the expected winning for a person purchasing one ticket

= 2000(.001) + 500(.003) + 100(.01) – 10(1)

= 2 + 1.5 + 1 – 10

= -5.5

 

The expected winning is -5.5. This implies that a person playing this lottery can expect to lose $5.50 for every one ticket that they purchase. 

7 0
3 years ago
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