Answer:
Explanation:
Potential energy is minus the integral of Fdx. Doing the integration yields:
so
Now for x=3.0m
If you mean electromagnetic waves
Radio waves can be used well in radio signals
Infrared in remote controls
X rays for x-rays
Gamma rays in a nuclear power plant
Uv rays can cause cancer but they transmit vitamin D
Answer:
The breast bone is anterior to the spine. The collarbone is superior to the shoulder blade. The elbow is proximal to the wrist. The navel is distal to the chin.
Explanation:
The spine, also known as the backbone, is posterior to the breast bone.
The collarbone (also known as the clavicle), which is part of the shoulder girdle, lies superior in position to the shoulder blade (also known as the scapula).
The elbow is the joint between the arm and the wrist. it is proximal to the wrist.
The navel, located on the anterior abdominal wall, is distal to the chin that is part of the face.
Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × 
/ ( 250 × π × 20 )
1300 × 
= (0.286)² × W × / ( 250 × π × 20 )
solve it and we get W
W = 249.56 × 
so elastic partial width is 2.49 eV
Answer:
69.42 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (vᵢ ) = 4.9 m/s
Acceleration (a) = 4.2 m/s²
Time (t) = 4.7 s
Displacement (Δx) =?
Thus, we can obtain the displacement by using the following formula:
Δx = vᵢt + ½at²
Δx = (4.9 × 4.7) + (½ × 4.2 × 4.7²)
Δx = 23.03 + (2.1 × 22.09)
Δx = 23.03 + 46.389
Δx = 69.419 ≈ 69.42 m
Thus, the distance travelled is 69.42 m
