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disa [49]
3 years ago
7

How much force is needed to accelerate a 1.5 kg physics book to an acceleration of 6 m/s^2?

Physics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

Force = 8.0 k g m / s

Explanation:

Force = mass x acceleration

Mass = 4.0 k g Acceleration = 2.0 m / s 2

Hence,force = ( 4.0 x 2.0 ) k g m / s 2 = 8.0 k g m / s 2

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at 1 p.m. a car traveling at a constant velocity of 78 km per hour towards the West it's 34 km to the west of our school how far
Fittoniya [83]

83 km/h * 2.5 hours (3:30 - 1:00) = 207.5 km  

207.5 km - 15 km = 192.5 km

3 0
3 years ago
Aluminum wire 1.00 mm in radius is to be used to construct a solenoid 15.0 mm in radius so that the magnitude of the magnetic fi
Leto [7]

To solve this problem we will proceed to use the equations given for the calculation of the resistance, in order to find the radius of the cable. Once the length is found we can find the number of turns of the solenoid and finally the net length of it

The resistance of the wire is

R= \frac{\rho L}{A}

\rho= Resistivity

L = Length

A = Cross-sectional Area

That can be also expressed as,

R = \frac{\rho L}{\pi r^2}

Rearranging the equation for the length of the wire we have

L= \frac{R\pi r^2}{\rho}

L= \frac{3\Omega \pi(1*10^{-3})}{2.655*10^{-8}\Omega \cdot m}

L = 354.8m

The number of turns of the solenoid is

N = \frac{L}{2\pi r} \rightarrow Denominator is equal to the circumference of the loop

N = \frac{354.8}{2\pi(15*10^{-3})}

N = 3766

Finally the Length of he solenoid is

l = N (\phi)

Where \phi is the diameter of wire

l = N (2r)

l = (3766)(2*(1*10^{-3}))

l = 7.532m

Therefore the length of the solenoid is 7.532m

7 0
4 years ago
Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile? Answ
Vinil7 [7]

Answer: 272.82 drop/tile

Explanation:

Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?

Tiles/ft^2 × drop/tiles = drop/ft^2

Tiles will cancel out. Leaving the answer to be drop/ ft^2

Substitutes all the magnitude of the above units.

17 × drop/tiles = 4638

Make drop/tiles the subject of formula

Drop/tiles = 4638/17

Drop/tiles = 272.82

Therefore, 272.82 drop/tile drops fall on each tile? 

8 0
3 years ago
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