Lifting weights, did this yesterday :))
Average velocity = (displacement) / (time)
Displacement = distance and direction between start and end points
Displacement = 25 km east
Average velocity = (25 km east) / (4 hours)
<em>Average velocity = 6.25 km/hr east</em>
Answer:
Final velocity will be 314.6 m/sec
Distance traveled = 1314.24 m
Explanation:
We have given initial velocity u = 233 m/sec
Acceleration 
Time t = 4.8 sec
From first equation of motion
, here v is final velocity, u is initial velocity and t is time
So 
Now we have to find distance traveled
From second equation of motion

So distance traveled in given time will be 1314.24 m
Explanation:
It is given that
The kinetic energy of Mr. Thomson’s prius, K = 641300 J
He is moving with a velocity, v = 22 m/s
It is required to find the mass of Mr. Thomson’s prius.
Due to his motion, a kinetic energy will possess by him. The mathematical form of kinetic energy is given by :

Solving for m

Plugging all the values, we get :

So, the mass of Mr. Thomson’s prius is 2650 kg.