Answer:
warm, dry downslope wind affecting Southern California - Santa Ana wind
a seasonally changing wind- monsoon
wind blowing from a valley up a mountain slope - valley breeze
generated by cold thunderstorm downdrafts - haboob
Explanation:
The Santa Ana wind occurs in early autumn. They bring hot and dry weather to areas around the South-West coast. They move at high speeds, affecting most parts of Southern California.
Monsoon is a seasonal wind that blows across Southern Asia. It usually blows in summer. It is a a seasonally changing wind.
Valley breeze is an example of convection current in nature. It is produced by rapid warming of the valley floor leading to the expansion of air making it to flow up the slopes. At night, radiation from the surface cools the slopes. This leads to the rise of cooler and denser air which drains into the valley.
Haboob is generated by cold thunderstorm downdrafts. It is associated with large sandstorms and dust storms.
Number of second in human lives in scientific notation is 3.9 × 10⁷ second
<u>Given that;</u>
Average human lives = 74 years
<u>Find:</u>
Number of second in human lives in scientific notation
<u>Computation:</u>
Number of second in human lives in scientific notation = 74 × 365 × 24 × 60
Number of second in human lives in scientific notation = 38,894,400
Number of second in human lives in scientific notation = 3.9 × 10⁷ second
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Answer:
31395 J
Explanation:
Given data:
mass of water = 150 g
Initial temperature = 25 °C
Final temperature = 75 °C
Energy absorbed = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 75 °C - 25 °C
ΔT = 50 °C
now we will put the values in formula
q = m . c . ΔT
q = 150 g × 4.186 J/g.°C × 50 °C
q = 31395 J
so, 150 g of water need to absorb 31395 J of energy to raise the temperature from 25°C to 75 °C .
0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess
P4)
<h3>How to calculate moles?</h3>
The balanced chemical equation is
The mass of clorine is m(
) = 58.0 g
The amount of clorine is n() = m()/M() = 58/70.906 = 0.817 mol
The stoichiometric reaction,shows that
10 moles of yield 4 moles of 
;
0.817 of yield x moles of
n() = 4*0.817/10 = 0.3268 mol
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