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atroni [7]
3 years ago
10

Simplify. 8u+9v+3u−5v What is the answer?

Mathematics
2 answers:
pochemuha3 years ago
8 0

8u + 9v + 3u - 5v = (8u + 3u) + (9v - 5v) = 11u + 4v

ladessa [460]3 years ago
8 0
=11u+4v would be the simplified answer
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If Josie wants to buy cupcakes and cookies for a party with a budget of
kolezko [41]

Answer:

50 cupcakes, 150 cookies

Step-by-step explanation:

3 0
3 years ago
Factor 200t+83 - 80t2.<br> A. 8t(t - 5)(t + 5)<br> B. 8t(t - 5)2<br> C. -8t(t - 5)(t + 5)
Mashutka [201]

Step-by-step explanation:

8t³-80t²+200t

= 8(t³-10t+25)

= 8t(t²-10t+25)

= 8t(t-5)(t-5)

= 8t(t-5)²

the answer is B.

3 0
3 years ago
A man is filling an empty 5-gallon bucket with water at a constant rate. there are 2.4 gallons of water in the bucket after fill
r-ruslan [8.4K]

Answer: The answer is 0.2

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0.2g/minutes

5 0
3 years ago
The horizontal line segment at the top of the polygon on the grid below is how many units long?​
Ymorist [56]

Answer:

6 units long.

Step-by-step explanation:

Given:

A polygon drawn on a graph.

In order to determine the distance of the horizontal line at the top, we find the coordinates of the end points and then use distance formula to find the exact distance.

Let us label the polygon as ABCD as shown below. AB is the length of the horizontal line.

Coordinates of A are (x_1,y_1)=(-3, 4) as seen in the graph.

Coordinates of B are (x_2,y_2)=( 3, 4) as seen in the graph.

Now, distance formula  for two points (x_1,y_1)\ and\ (x_2,y_2) is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d_{AB}=\sqrt{(3-(-3))^2+(4-4)^2}\\d_{AB}=\sqrt{(3+3)^2+0}\\d_{AB}=\sqrt{36}=6\ units

Therefore, the horizontal line at the top is 6 units long.

4 0
4 years ago
Solve for points. identify the vertex and indicate whether it is max or min.
Keith_Richards [23]

Answer:

min at (3, 0 )

Step-by-step explanation:

given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = (x - 3)² = x² - 6x + 9 ← in standard form

with a = 1 and b = - 6 , then

x_{vertex} = - \frac{-6}{2} = 3

substitute x = 3 into the equation for corresponding value of y

y = (3 - 3)² = 0² = 0

vertex = (3, 0 )

• if a > 0 then vertex is minimum

• if a < 0 then vertex is maximum

here a = 1 > 0 then (3, 0 ) is a minimum

4 0
2 years ago
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