Answer:
The solution code is written in Python:
- items = [{"id": 37697, "code": ""},{"id": 37698, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""}, {"id": 37699, "code": ""},
- {"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37700, "code": ""} ]
-
- items[0]["code"] = 1
-
- for i in range(1, len(items)):
- if(items[i]["id"] == items[i-1]["id"]):
- items[i]["code"] = items[i-1]["code"] + 1
- else:
- items[i]["code"] = 1
-
- print(items)
Explanation:
Firstly, let's create a list of dictionary objects. Each object holds an id and a code (Line 1-2). Please note all the code is initialized with zero at the first beginning.
Next, we can assign 1 to the <em>code</em> property of items[0] (Line 4).
Next, we traverse through the items list started from the second element (Line 6). We set an if condition to check if the current item's id is equal to the previous item (Line 7). If so, we assign the previous item's code + 1 to the current item's code (Line 8). If not, we assign 1 to the current item's code (Line 10).
At last, we print out the item (Line 12) and we shall get
[{'id': 37697, 'code': 1}, {'id': 37698, 'code': 1}, {'id': 37699, 'code': 1}, {'id': 37699, 'code': 2}, {'id': 37699, 'code': 3}, {'id': 37699, 'code': 4}, {'id': 37699, 'code': 5}, {'id': 37699, 'code': 6}, {'id': 37700, 'code': 1}]
