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3 years ago

What is 90 to the power of 46

Engineering

1 answer:

Mnenie [13.5K]3 years ago

6 0

Answer:Just multiply 90 by itself 46 times

Explanation:

do it

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This test should be performed on all cord sets, receptacles that aren't part of a building or structure's permanent wiring, and

vova2212 [387]

Answer:

A continuity test

Explanation:

A continuity test is used to verified that current will flow in an electrical circuit, it performed by placing a small voltage across the chosen path. continuity test ensure that the equipment grounding conductor is electrically continuous and this test is perform on all the cord sets, receptacles that aren't part of a building or structure's permanent wiring, and cord-and-plug connected equipment required to be grounded. example of equipment used in testing current flow in continuity test are Analog multi-meter, voltage/continuity tester etc.

Continuity test and terminal connection test are the two test required by OSHA on all electrical equipment

8 0

3 years ago

Write a simple phonebook program that reads in a series of name-number pairs from the user (that is, name and number on one line

Vlad1618 [11]

Answer:

import java.util.HashMap;

import java.util.Map;

import java.util.Scanner;

public class PhoneBook {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

Map<String, String> map = new HashMap<>();

String name, number, choice;

do {

System.out.print("Enter name: ");

name = in.next();

System.out.print("Enter number: ");

number = in.next();

map.put(name, number);

System.out.print("Do you want to try again(y or n): ");

choice = in.next();

} while (!choice.equalsIgnoreCase("n"));

System.out.print("Enter name to search for: ");

name = in.next();

if (map.containsKey(name)) {

System.out.println(map.get(name));

} else {

System.out.println(name + " is not in the phone book");

}

6 0

3 years ago

Assume the average fuel flow rate at the peak torque speed (1500 rpm) is 15kg/hr for a sixcylinder four-stroke diesel engine und

sveticcg [70]

Answer:

Q = 8.845 DEGREE

Explanation:

given data:

combine Mass for 6 cylinder (M) =15 Kg/hr

mass of each cylinder (m) = 15/6 = 2.5 Kg/hr = 0.000694 Kg/ sec

Engine speed (N)= 1500rpm

Diameter of one nozzle hole ( d) = 200 micrometer = 0.0002 m

Discharge Coefficient (Cd) = 0.75

Pressure difference = 100 MPa

Density of fuel = 800 kg/m^3

velocity of fuel is $v = cd\sqrt{\frac{2*P}{p}}$

$v = 0.75 \sqrt{\frac{2\times 100\times 10^6}{800}} = 375 m/sec$

injected fuel volume (V) =Area of given Orifices × Fuel velocity × time of single injection × no of injection/sec

we know that p = m/ V

So $V = \frac{0.000694}{800} =8.68\times10^{-7} m3/sec$

putting these value in volume equation and solve for Discharge $8.68\times 10^{-7} = (\frac{(3.14}{4})\times 6\times( .0002\times .0002) \times 375 \times \frac{(Q}{360}) \times \frac{30}{750} \times \frac{(750}{60)}$

Q = 8.845 DEGREE

4 0

3 years ago

A westbound section of freeway currently has three 12-ft wide lanes, a 6-ft right shoulder, and no ramps within 3 miles upstream

alisha [4.7K]

Answer:

The level of the service is loss and the density is 34.2248 pc/mi/ln

Explanation:

the solution is attached in the Word file

Download docx

6 0

3 years ago

Karl and Susan have agreed to come to our party, _______ has made Maria very happy. that which what who

Aleks04 [339]

Answer:

that

I am not sure that this is the answer

but i hopethis will help you

4 0

3 years ago