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Alexxx [7]
3 years ago
13

4. Which of the following is the first thing you should do when attempting

Engineering
2 answers:
Hoochie [10]3 years ago
6 0

hey there! i am not really good at this topic, but I’m pretty sure the answer is C.

let me know if you get it right! :)

Klio2033 [76]3 years ago
3 0

Answer: B. Turning on your hazard lights.

Explanation:

Because...

that indicates the drive behind you to go in front of you and indicator lights that flash in unison to warn other drivers that the vehicle is a temporary obstruction.

* Hopefully this helps:) Mark me the brainliest:)!!!

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In normal operation, a paper mill generates excess steam at 20 bar and 400◦C. It is planned to use this steam as the feed to a t
Keith_Richards [23]

Answer:

The maximum power that can be generated is 127.788 kW

Explanation:

Using the steam table

Enthalpy at 20 bar = 2799 kJ/kg

Enthalpy at 2 bar = 2707 kJ/kg

Change in enthalpy = 2799 - 2707 = 92 kJ/kg

Mass flow rate of steam = 5000 kg/hr = 5000 kJ/hr × 1 hr/3600 s = 1.389 kg/s

Maximum power generated = change in enthalpy × mass flow rate = 92 kJ/kg × 1.389 kg/s = 127.788 kJ/s = 127.788 kW

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There is a dispute between the multiple parties storing financial transaction data on a blockchain over the validity of a transa
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5 0
2 years ago
What is differences Between hard shoulder & soft shoulder in civil Engineerin?
r-ruslan [8.4K]

Answer:

<em><u>The 'shoulder' of a road is the land to the edge of the road. On most roads without pavements, the shoulder is a strip of grass or a hedgerow. This is known as a 'soft shoulder'. On a motorway, this strip of land is hardstanding, hence the name 'hard shoulder.'</u></em>

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5 0
3 years ago
Water flows through a nozzle at the end of a fire hose. If the nozzle exit velocity must be 20 m/s and the exit diameter is 40 m
lara31 [8.8K]

Answer:

minimum flow rate provided by pump is 0.02513 m^3/s

Explanation:

Given data:

Exit velocity of nozzle = 20m/s

Exit diameter = 40 mm

We know that flow rate Q is given as

Q = A \times V

where A is Area

A =\frac{\pi}{4} \times (40\times 10^{-3})^2 = 1.256\times 10^{-3} m^2

Q = 1.256\times 10^{-3} \times 20 = 0.02513 m^3/s

minimum flow rate provided by pump is 0.02513 m^3/s

5 0
3 years ago
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