Answer:
a) Δd(change in wood diameter) = 5%
b) The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter
C) new diameter (D2) = 10.5 in
Explanation:
Wood pole diameter = 10 inches
moisture content = 5%
FSP = 30%
A) The percentage change in the wood's diameter
note : moisture fluctuations from 5% to 30% causes dimensional changes in the wood but above 30% up to 55% causes no change. hence this formula can be used to calculate percentage change in the wood's diameter
Δd/d = 1/5(30 - 5)
Δd/d = 5%
Δd = 5%
B) would the wood swell or shrink
The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter
C) The new diameter of the wood
D2 = D + D(
)
D = initial diameter= 10 in , M1 = initial moisture content = 5%
therefore D2 = 10 + 10( 5/100 )
new diameter (D2) = 10.5 in
Answer:
Benefits that last a lifetime. The Army offers you money for education, comprehensive health care, generous vacation time, family services and support groups, special pay and cash allowances to cover the cost of living.
Answer:
LOTS
Explanation:
Catapults, Towers, and Trebuchets were all used by Saladin to capture Jerusalem in 1187
Answer: A) Product identifier
Explanation:
A product identifier is a means, name or number used to identify hazardous and dangerous chemicals on a label or in the SDS( safety data sheet). It provides a special means which helps the user to identify the chemical. Any product identifier used should permit a cross-references to be made among the listed hazardous chemicals required in the written hazard communication program, and the label including SDS(safety data sheet).
Answer:
1.1451 x 104 (11451.13)mg/m3
Explanation:
1 ppmv is defined as one volume of a contaminant or solid(CO)(mL) in 1 x 106 volume of solvent/water.
1ppmv = 1mL/m3
Concentration in mg/m3 = volume in ppm x molecular weight x pressure(kPa)/( gas constant x temperature(K)
Molecular weight of CO = 12 + 16
= 28g/mol
Temperature = 273.15 + 25
= 298.15K
Pressure = 1 x 101.325kPa
= 101.325kPa
Ppmv = 1 x 10-4ppmv
Gas constant, R = 8.3144 L.kPa/mol.K
Concentration in mg/m3 = (1 x 104 * 28 * 101.325)/(8.3144 * 298)
= 1.1451 x 104mg/m3
= 11451.13 mg/m3