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2 years ago

All of the dimensions on an aircraft drawing are_________ to the bottom of the drawing.

Engineering

1 answer:

Jet001 [13]2 years ago

7 0

All of the dimensions on an aircraft drawing are _________ to the bottom of the drawing

Answer: parallel

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15 POINTS! Help.

IRISSAK [1]

Answer: it would overload

Explanation:

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3 years ago

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After testing a model of a fuel-efficient vehicle, scientists build a full-sized vehicle with improved fuel efficiency. Which st

Mazyrski [523]

B evaluate the solution. Sorry if I'm wrong.

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3 years ago

The local atmospheric pressure is measured with a water barometer. If the water column is measured to be 30 ft, what is the atmo

ella [17]

Answer:

The atmospheric pressure in atm=0.885 atm

Explanation:

Given that

Local pressure (h)= 30 ft of water height ( 1 ft= 0.3048 m)

We know that pressure in given by

P=ρgh

We know that ρ of water is 1000 $\dfrac{kg}{m^3}$

So pressure

P=1000(9.81)(9.144)

$P=89.7026 \dfrac{N}{m^2}$

We know that 1000 Pa=0.00986 atm

So P=0.885 atm

The atmospheric pressure in atm=0.885 atm

8 0

3 years ago

Given the following phasors and the information related to the frequency of that phasor, provide the corresponding time-domain r

Evgesh-ka [11]

Answer:

Explanation:

In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.

For the step by step solution to the question you asked, go through the attached documents.

4 0

3 years ago

g A circular oil slick of uniform thickness is caused by a spill of one cubic meter of oil. The thickness of the oil slick is de

Anika [276]

Answer:

the rate of increase of radius is dR/dt = 0.804 m/hour = 80.4 cm/hour

Explanation:

the slick of oil can be modelled as a cylinder of radius R and thickness h, therefore the volume V is

V = πR² * h

thus

h = V / (πR²)

Considering that the volume of the slick remains constant, the rate of change of radius will be

dh/dt = V d[1/(πR²)]/dt

dh/dt = (V/π) (-2)/R³ *dR/dt

therefore

dR/dt = (-dh/dt)* (R³/2) * (π/V)

where dR/dt = rate of increase of the radius , (-dh/dt)= rate of decrease of thickness

when the radius is R=8 m , dR/dt is

dR/dt = (-dh/dt)* (R³/2) * (π/V) = 0.1 cm/hour *(8m)³/2 * π/1m³ *(1m/100 cm)= 0.804 m/hour = 80.4 cm/hour

4 0

3 years ago