Answer:
Number of rollers required to complete the compaction are 2
Explanation:
The solution is given in the attachments.
Answer:
The maximum power that can be generated is 127.788 kW
Explanation:
Using the steam table
Enthalpy at 20 bar = 2799 kJ/kg
Enthalpy at 2 bar = 2707 kJ/kg
Change in enthalpy = 2799 - 2707 = 92 kJ/kg
Mass flow rate of steam = 5000 kg/hr = 5000 kJ/hr × 1 hr/3600 s = 1.389 kg/s
Maximum power generated = change in enthalpy × mass flow rate = 92 kJ/kg × 1.389 kg/s = 127.788 kJ/s = 127.788 kW
Lo siento, no sé qué estás diciendo.
Answer:
» Microsoft word ( word processing )
» Microsoft powerpoint ( presentation )
» Microsoft access ( database mamagement )
» Microsoft excel ( spread sheets )
Explanation:
