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3 years ago

MEDAL AND FAN FOR FIRST ANSWER!!!!

1 answer:

8 0

The answer is C. <span>copper penny. The other options are not conductors, but rather they are insulators. They do not let electricity to passed by an object. Most of metallic objects are considered as conductors because metals attract with electrons since it is positively charged.</span>

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Question 1

frez [133]

B 20 m/s
It should go to 100 that fast nor 40

4 0

3 years ago

There is more than one answer

Sveta_85 [38]

Explanation:

the answers are the first 3.

5 0

3 years ago

Read 2 more answers

Water is stored in 5 places on earth.Name each place an dnote the phrase that water is in liquid solid,gas

podryga [215]

Atmosphere - gas
sea and oceans - liquid and solid
land -liquid and solid
living things and plants - liquid

6 0

3 years ago

Every few hundred years most of the planets line up on the same side of the Sun.(Figure 1)Calculate the total force on the Earth

mylen [45]

Answer: $3.7 \times 10^{-4} N$

Explanation:

The gravitational pull between two object is given by:

$F = G\frac{Mm}{r^2}$

Where M and m are the masses of the object, r is the distance between the masses and G = 6.67× 10⁻¹¹ m³kg⁻¹ s⁻² is the gravitational constant.

We have to calculate the net force on Earth due to Venus, Jupiter and Saturn when they are in one line. It means when they are the closest distance.

$F_{net] = G\frac{M_eM_v}{r_v^2}+G\frac{M_eM_j}{r_j^2}+G\frac{M_eM_s}{r_s^2}$

Mass of Earth, Me = 5.98 × 10²⁴ kg

Mass of Venus, Mv = 0.815 Me

Mass of Jupiter, Mj = 318 Me

Mass of Saturn, Ms = 95.1 Me

closest distance between Earth and Venus, rv = 38 × 10⁶ km = 0.25 AU

closest distance between Jupiter and Earth, rj = 588 × 10⁶ km = 3.93 AU

closest distance between Earth and Saturn, rs = 1.2 × 10⁹ km = 8.0 AU

where 1 AU = 1.5 × 10¹¹ m

Inserting the values:

$F_{net} = G\frac{M_e\times 0.815 M_e}{(0.25AU)^2}+G\frac{M_e\times 318 M_e}{(3.93AU)^2}+G\frac{M_e\times 95.1 M_e}{(8.0AU)^2}\\ \Rightarrow F_{net} = \frac{(GM_e^2)}{(1AU)^2}(\frac{0.815}{0.25^2}+\frac{318}{3.93^2}+\frac{95.1}{8.0^2})=\frac{6.67\times 10^{-11} \times (5.98\times 10^{24})^2}{(1.5\times 10^{11})^2}(35.1) = 3.7 \times 10^{-4} N$

4 0

3 years ago

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The peak intensity of radiation from a star named sigma is 2 x 10^6 mmkay. What is the average surface temperature of Sigma roun

Igoryamba

Answer:

1.45 K

I had the same question and i got it right.

8 0

4 years ago

Read 2 more answers