The electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.
<h3>
Electric field of the positive particle</h3>
The electric field is calculated as follows;
E = kq/r²
where;
- r is the distance between the charges
- k is Coulomb's constant
- q is magnitude of the charge
midpoint of 3.08 m, x = 1.54 mm
r(1.54 mm, 2.00 mm)
|r| = √(1.54² + 2²)
|r| = 2.52 mm
E = (9 x 10⁹ x 37.3 x 10⁻³)/(2.52 x 10⁻³)²
E = 5.287 X 10¹³ N/C
Thus, the electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.
Learn more about electric field here: brainly.com/question/14372859
#SPJ1
<span>None of the light passes through it; some of the light is absorbed as heat but most is reflected off the surface. This is how you see </span>objects. reflected light from them hits your eye. (Opaque means not transparent)
Speed = (distance covered) / (time to cover the distance)..
From the ground to the highest point,
the rocket's AVERAGE speed is
(86 m) / (3.7 sec) = 23.2 m/s (rounded) .
Answer:
Her measurements will be more accurate if she uses a cloth tape
measure instead of a ruler.
Explanation: (apex)
