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2 years ago

Write the chemical equation that describes how calcium carbonate neutralizes acid

Chemistry

2 answers:

olchik [2.2K]2 years ago

8 0

Answer:

$CaCO_3+2HCl-->CaCl_2+CO_2+H_2O$

Explanation:

Hello,

Typically, calcium carbonate is suitable to neutralize specifically hydrochloric acid via the required chemical reaction which is shown below:

$CaCO_3+2HCl-->CaCl_2+CO_2+H_2O$

Carbon dioxide and water are yielded as carbonic acid is firstly yielded but it is unstable enough to be segregated into carbon dioxide and water. In addition, calcium chloride is yielded as an evidence of the acid's neutralization.

Best regards.

enyata [817]2 years ago

6 0

<h3><u>Answer;</u></h3>

CaCO3(s)+ 2 H+(aq) → Ca+2 + CO2(g) + H2O(l)

<h3><u>Explanation</u>;</h3>

The reaction of an acid with calcium carbonate is an example of an acid-base reaction.
In these reactions, an acid will react with a base to form a salt and water. The acid was neutralized by the base.

For example, CaCo3 will neutralize HCl by the following equation:

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Which of these rocks forms from lava that cools very quickly?

den301095 [7]

The answer is D. obsidian. Or at least I think it is. Just guessing based off me playing Minecraft 6 years ago haha

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3 years ago

A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31

Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

$PV = nRT$

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

$n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles$

Now, we can find the temperature with the final conditions:

$T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K$

The temperature in Celsius is:

$T_{2} = 274.7 - 273 = 1.7 ^{\circ} C$

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!

8 0

2 years ago

_____ are chemical substances that bind with a receptor and activate the receptor, much like a neurotransmitter does.

Viefleur [7K]

Answer:

Ligands

Explanation:

Ligands are small molecules that transmit signals in between or within cells. Ligands exert their effects by binding to cellular proteins called receptors.

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2 years ago

Which of the following 0.820 M solutions would have the greatest colligative effect?

eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0

2 years ago

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of

Yanka [14]

Answer:

Mass of carbon dioxide produced = 52.8 g

Explanation:

Given data:

Mass of carbon react = 14.4 g

Mass of oxygen = 56.5 g

Mass of oxygen left = 18.1 g

Mass of carbon dioxide produced = ?

Solution:

C + O₂ → CO₂

Number of moles of C:

Number of moles = mass/ molar mass

Number of moles = 14.4 g/ 12 g/mol

Number of moles = 1.2 mol

18.1 g of oxygen left it means carbon is limiting reactant.

Now we will compare the moles of C with CO₂.

C : CO₂

1 : 1

1.2 : 1.2

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.2 mol × 44 g/mol

Mass = 52.8 g

8 0

2 years ago