Construct a graph of position versus time for the motion of a dog, using the data in the table below. Explain how the graph indi
cates that the dog is moving at a constant speed.
1 answer:
Answer:
The dog is moving at a constant speed
Explanation:
Given that,
Position : 5, 10, 15, 20, 25
Time = 5. 10, 15, 20, 25
We need to draw a position time graph
Using given data
A graph of position and time shows the speed.
According to graph,
The graph indicates that the dog is moving at a constant speed because the graph is straight line.
Hence, The dog is moving at a constant speed
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Answer:
1) Final Temperature of the gas in A will be GREATER than the temperature in B
2) Diagram of both processes on a single PV has been uploaded below
3) The Initial pressures in containers A and B is 3039.87 J/liters
4) the final volume of container B is 923.36 cm³
Explanation:
Given that;
Temperature = 20°C = 293 K
mass of piston = 10 kg
Area = 100cm³
Volume V = 800 cm³ = 0.8 L
ideal gas constant R = 8.3 J/K·mol
1)
Final Temperature of the gas in A will b GREATER than the temperature in B
2)
Diagram of both processes on a single PV has been uploaded below,
3)
Initial pressures in containers A and B
PV = nRT
P = RT/V
we substitute
P = (8.3 × 293) / 0.8
P = 2431.9 / 0.8
P = 3039.87 J/liters
Therefore, The Initial pressures in containers A and B is 3039.87 J/liters
4)
Given that;
power = 25 W
time t = 15s
the final volume of container B = ?
we know that;
work done = power × time
work done = 25 × 15 = 375
Also work done = P( V₂ - V₁ )
so we substitute
375 = 3039.87 ( V₂ - 0.8 )
( V₂ - 0.8 ) = 375 / 3039.87
V₂ - 0.8 = 0.12336
V₂ = 0.12336 + 0.8
V₂ = 0.92336 Litres
V₂ = 923.36 cm³
Therefore, the final volume of container B is 923.36 cm³
Answer:
Explanation:
The electric field is defined as the electric force per unit of charge, this is:
.
The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as
.
By substitution we get that
Now, letting be the electric field at point A, letting
be the electric field at point B, and letting R be the distance from the charge to A:
.
The ration of the electric fields is
This means that at half the distance, the electric field is four times stronger.