Yes, you could have a mixture noble gases. They are inert so they will remain in their elemental form and still form a mixture without reacting together.
Answer:
a. 0.5 mol
b. 1.5 mol
c. 0.67
Explanation:
Fe3+ + SCN- -----> [FeSCN]2+
a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium
b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium
c. KC = 0.5/(0.5*1.5) = 0.67
Answer:
The given equation is not balanced.
Explanation:
Chemical equation:
3H₂ + 3Cl₂ → HCl
The balanced equation always have equal number of atoms on both side of equation. In this equation on left side there are six atoms of chlorine and six atoms of hydrogen are present while on right side only one atom of hydrogen and one atom of chlorine are present.
The balanced equation always follow the law of conservation of mass.
According to the law of conservation of mass, mass can neither be created nor be destroyed in a chemical reaction.
It means reactant and product always have same mass.
The given equation can written as balanced equation as follows,
Balanced chemical equation:
3H₂ + 3Cl₂ → 6HCl
There are equal number of atoms of hydrogen and chlorine are present on both side of equation so it follow the law of conservation of mass.
Answer:
2.3125g
Explanation:
Half-life referred to the time required for a quantity to reduce to half of its initial value, It used to calculate how unstable atoms undergo, or the period of time and atom can survive, radioactive decay.
Given:
t(1/2)= 9.25days
Initial mass of Thulium-167 = 48grams
We need to calculate the remaining amount after 37days.
Since we know that 1 half life = 9.25 days
Then 37 days means ( 37/9.25) half lives
37days means 4 half life
That means the 38grams of Thulium-167 will be halved by 4 times.
Then the ratio between the initial Amount and the amount remaining after 37 days can be calculated as. 0.5^(4)
= 37days × 0.5^(4)
= 2.3125g
the remaining amount of Thallium-167 after 37days is 2.3125g
